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Amanda [17]
3 years ago
14

Definition of Speed?​

Physics
2 answers:
Nitella [24]3 years ago
5 0

speed- the rate something moves or operates

Can I have brainlist please

ANEK [815]3 years ago
4 0

Explanation:

speed of an object is the magnitude of the rate of change of its position with time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.

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A stationary boat in the ocean is experiencing waves from a storm. the waves move at 56 km/h and have a wavelength of 160 m, bot
Lera25 [3.4K]
The wavelength \lambda of the wave is 160 m, and this is the distance between two consecutive crests. The boat is located at a crest of the wave, this means that the first trough is located 80 meters from the boat (because the distance between a crest and a trough is half the wavelength).

The speed of the wave is 
v=56 km/h = 15.6 m/s
so the time the boat takes to reach the first trough is
t= \frac{S}{v} = \frac{80 m}{15.6 m/s}=5.1 s
5 0
4 years ago
How can we show the magnetic force of a magnet illustrate with an example​
morpeh [17]

Answer:

take some sharp mixture of iron spread it from up the magnet you will see the magnetic field of magnet

3 0
3 years ago
Letters A B, C and D represent locations on a bar magnet. Which location has the greatest magnetic force? (l) A (3) C ets (2) B
Elena L [17]
Answer: The magnetic field of a bar magnet is strongest at either pole of the magnet. It is equally strong at the north pole compared with the south pole. The force is weaker in the middle of the magnet and halfway between the pole and the center. So it would be D.

6 0
3 years ago
A bullet is fired straight up from a gun with a
melamori03 [73]

Answer: 815.51 m

Explanation:

This situation is related to projectile motion or parabolic motion, in which the initial velocity of the bullet has only y-component, since it was fired straight up. In addition, we are dealing with constant acceleration (due gravity), therefore the following equations will be useful to solve this problem:

V=V_{o}+gt (1)

V^{2}=V_{o}^{2}+2gy (2)

Where:

V is the final velocity of the bullet

V_{o}=152 m/s is the initial velocity of the bullet

g=-9.8 m/s^{2} is the acceleration due gravity, always directed downwards

t=6.9 s is the time

y is the vertical position of the bullet at t=6.9 s

Let's begin by finding V from (1):

V=152 m/s-9.8 m/s^{2}(6.9 s) (3)

V=84.38 m/s (4)

Now we have to substitute (4) in (2):

(84.38 m/s)^{2}=(152 m/s)^{2}-2(9.8 m/s^{2})y (5)

Isolating y:

y=815.511 m This is the displacement  of the bullet after 6.9 s

8 0
3 years ago
An object is pushed with a force of 400 N for 20 meters; what is the work done on the object? Solve using W=F*d
nika2105 [10]

Answer:

W = Fd = 400(20) = 8000 J

Explanation:

5 0
3 years ago
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