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Zanzabum
3 years ago
7

A little boy is being pushed in a wagon by his mother. Suddenly, the little boy's mother stops to watch for cars before she cros

ses the street. The little boy's body continues to move forward in the stopped wagon until he tumbles out. The forward movement of the boy's body shows – *
A) Newton's law of gravity.
B) Newton's law of inertia.
C) Newton's law of force and acceleration.
D) Newton's law of action-reaction.
Chemistry
2 answers:
Y_Kistochka [10]3 years ago
4 0
I’m pretty sure it’s “C”
Free_Kalibri [48]3 years ago
3 0

Answer:

the answer would be C

i took this from a quizlet

hopes this helps<3

You might be interested in
1. A balloon contains 100g of oxygen gas (O₂) when the volume is 110 dm³. Find the volume of the balloon when the mass of oxygen
igor_vitrenko [27]

The volume of the balloon when the mass of oxygen gas is decreased to 50g is 50L.

We will use the ideal gas equation-

<u>PV=nRT</u>

P=Pressure

V=volume

n=no. of moles

T=temperature

In this question temperature and pressure will remains constant then the above equation can be rewritten as-

V_{1} /n_{1} =V_{2} /n2

where V1= initial volume of the balloon

            V2=  volume of the balloon when the mass of oxygen gas is decreased to 50g

now, substitute the values in the above equation-

  • V1=100dm3=100L
  • n1=100/32=3.12
  • n2=50/32=1.56

       100/3.12=V2/1.56

  • V2=50 L

hence, the volume of the balloon when the mass of oxygen gas is decreased to 50g is 50L.

learn more about the ideal gas equation here:

brainly.com/question/1056445

#SPJ10

3 0
2 years ago
How many protons, electrons, and neutrons does an atom with atomic number
sergey [27]

Answer:

protons : 10

electron : 10

neutron : 10

Explanation:

Protons will usually be the same as the electrons when its a <u>Atom</u> (when its a ion or covalent bond or simple bond they will most likely be different)

the atomic number represents protons and electrons

the mass number - the atomic number = neutron

8 0
3 years ago
What are its electron-pair and molecular geometries? What is the hybridization of the nitrogen atom? What orbitals on and overla
jok3333 [9.3K]

Answer:

Electron-pair geometry: tetrahedral

Molecular geometry: trigonal pyramidal

Hybridization: sp³

sp³ - 4 p

Explanation:

There is some info missing. I think this is the original question.

<em>For NBr₃, What are its electron-pair and molecular geometries? What is the hybridization of the nitrogen atom? What orbitals on N and Br overlap to form bonds between these elements?</em>

<em>The N-Br bonds are formed by the overlap of the  ___ hybrid orbitals on nitrogen with ___ orbitals on Br.</em>

<em />

Nitrogen is a central atom surrounded by 4 electron domains. According to VESPR, the corresponding electron-pair geometry is tetrahedral.

Of these 4 electron domains, 3 represent covalent bonds with Br and 1 lone pair. According to VESPR, the corresponding molecular geometry is trigonal pyramidal.

In the nitrogen atom, 1 s orbital and 3 p orbitals hybridize to form 4 sp³ orbitals for each of the electron domains.

The N-Br bonds are formed by the overlap of the sp³ hybrid orbitals on nitrogen with 4p orbitals on Br.

7 0
3 years ago
11. Which of the following hydrocarbons would you expect to have the highest boiling point?
vaieri [72.5K]
Ethane should be the answer!
4 0
3 years ago
A cup holding 125.12g of water has an initial temperature of 26.8 degrees C. After a 35.08g piece of metal, at 99.5 degrees C, i
nignag [31]
<h3>Answer:</h3>

0.620 J/g°C

<h3>Explanation:</h3>

Heat gained or absorbed, Q by a substance is calculated by;

Q = mass × specific heat capacity × Change in temperature

In this case we are given;

  • Mass of water = 125.12 g
  • Initial temperature of water = 26.8 °C
  • Initial temperature of the metal = 99.5°C
  • Final temperature of the mixture = 29.7 °C

We are required to calculate the specific heat capacity of the metal;

<h3>Step 1 : Heat absorbed by water </h3>

Specific heat capacity of water = 4.184 J/g°C

Temperature change of water = 29.7 °C - 26.8°C

                                                   = 2.9 °C

But, Q = m×c×ΔT

Thus, Heat = 125.12 g × 2.9°C × 4.184 J/g°C

                  = 1518.156 Joules

<h3>Step 2; Heat lost by the metal </h3>

Specific heat capacity of the metal = x J/g°C

Temperature change of the metal = 29.7 °C - 99.5°C

                                                         = -69.8 °C

But, Q = mcΔT

Therefore;

Heat lost by the meatl = 35.08 g × x J/g°C × 69.8 °C

                                     = 2.448.584x Joules

<h3>Step 3: C;aculating the specific heat capacity of the metal </h3>

The heat gained by water is equal to the heat lost by the metal

Therefore;

1518.156 Joules = 2.448.584x Joules

x = 1518.156 J ÷ 2.448.584 J

   = 0.620 J/g°C

Therefore, the specific heat of the metal is 0.620 J/g°C

8 0
4 years ago
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