There are 1.66 1 molecules in 1 gram of nicotine.
<u>Explanation</u>:
Nicotine is an organic compound with the chemical formula of
Given the mass of nicotine = 4.50 g
Molecular mass of Nicotine = 162.23 g/mol
Moles of a compound = given mass / molar mass of the compound
=
The Number of molecules of compound:
Moles Avogadro number = 0.0277 6.023 1
= 1.66 1 molecules.
There are 1.66 1 molecules in 1 gram of nicotine.
He thought it looked like plum pudding, with positively charged balls(pudding) and negatively charged raisins
Molal concentration gives the number of moles dissolved in 1 kg of solution.
Molal concentration of H₂SO₄ is 2.88 mol/kg
the weight of H₂SO₄ in 1 kg - 2.88 mol x 98 g/mol = 282.2 g
The total weight of solution - 1000 g + 282.2 g = 1282.2 g
density of solution is 1.167 g/ml
We need to find how many moles are dissolved in 1 L.
We know the weight of the solution, using this we can calculate volume of the solution
volume of solution is - 1282.2 g / 1.167 g/mL = 1098.7 mL
The number of H₂SO₄ moles in 1.0987 L = 2.88 mol
Therefore in 1 L = 2.88 mol / 1.0987 L = 2.62 mol
Molarity of H₂SO₄ is 2.62 mol/L = 2.62 M
V1/T1 = V2/T2
V1= 3.5 L
T1 = 25 +273=298 K
T2 = 40.9 + 273 = 313.9 K
V2- ?
3.5 L/298 K= V2/ 313.9 K
V2 = (3.5 L*313.9 K)/298 K ≈ 3.69 L