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Artyom0805 [142]
3 years ago
13

Guía resuelta fase 2 semana 3 ciencias 9° grado​

Chemistry
1 answer:
Lina20 [59]3 years ago
4 0

Answer:

hi im andre and im 14

Explanation:

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What type of energy is the sum of kinetic and potetinal energy in an object that is used to do work
wolverine [178]

Answer:

mechanical energy

Explanation:

6 0
3 years ago
How many grams are there in 3.4 x 10^24 atoms of He?
Lelechka [254]

Given :

Number of He atoms, n = 3.4\times 10^{24} atoms.

To Find :

How many grams are their in given number of He atoms.

Solution :

We know, molecular mass of He is 4 g. It means that their are 6.022 \times 10^{23} atoms in 4 g of He.

Let, number of gram He in 3.4\times 10^{24} atoms is x , so :

x = \dfrac{3.4\times 10^{24}}{6.022\times 10^{23}}\times 4\\\\x =  $$22.58\ g

Therefore, grams of He atoms is 22.58 g .

5 0
3 years ago
What does geocentric mean
motikmotik

Answer:

Relating to, measured from, or as if observed from the earth's center.

5 0
3 years ago
Read 2 more answers
Write a balanced half-reaction for the reduction of bismuth oxide ion to bismuth ion in basic aqueous solution. Be sure to add p
Butoxors [25]

Answer:

3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-

Explanation:

Hello there!

In this case, according to the required half-reaction, we start by setting it up from bismuth (V) oxide ion to bismuth (III) ion:

BiO_3^-\rightarrow Bi^{3+}

Thus, next realize that the oxidation state of Bi in BiO3^- is 5+ because oxygen is 2- (-2*3+x=-1;x=-1+6;x=+5), so we obtain:

(Bi^{5+}O_3)^-\rightarrow Bi^{3+}

Thereafter, we realize three water molecules are needed on the right in order to balance the oxygens and consequently 6 hydrogen atoms on the left to balance hydrogen:

6H^++(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O

Now, since the balance is is basic media, we add six molecules of hydroxide ions in order to produce water with the hydrogen ones:

6OH^-+6H^++(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O+6OH^-\\\\6H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O+6OH^-\\\\6H_2O-3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-

Then, we accommodate the waters to obtain:

3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-

Best regards!

7 0
3 years ago
We gave an object with a density of 620 g/cm^3 and a volume of 75cm^3. What is the mass of this object?
Hitman42 [59]
d=\frac{m}{V} \ \ \ \Rightarrow \ \ m=dV\\\\
d=620\frac{g}{cm^{3}}\\
V=75cm^{3}\\\\\
m=620\frac{g}{cm^{3}}*75cm^{3}=46500g
6 0
4 years ago
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