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Inessa [10]
3 years ago
14

A 1.5 M solution of NaOH was made in a laboratory. If the solution made had a volume of 4.5 L, how many grams of NaOH were added

?
Chemistry
1 answer:
Crank3 years ago
6 0

Answer:

270g

Explanation:

Given parameters:

Concentration of NaOH  = 1.5M

Volume  = 4.5L

Unknown

Mass of NaOH added  = ?

Solution:

To solve the problem, we need to find the number of moles of the NaOH first;

 Number of moles  = concentration x volume

 Number of moles  = 1.5 x 4.5  = 6.75mol  

Now;

  Mass  = Number of moles x molar mass

 Molar mass of NaOH  = 23 + 16 + 1  = 40g/mol

  Mass  = 6.75 x 40  = 270g

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How many milliliters of 2.5 M HCl are required<br> to exactly neutralize 1.5 L of 5.0 M NaOH?
Airida [17]

Answer:

3000mL

Explanation:

The following data were obtained from the question:

Volume of acid (Va) =..?

Molarity of acid (Ma) = 2.5M

Volume of base (Vb) = 1.5L

Molarity of base (Mb) = 5M

Next, we shall write the balanced equation for the reaction. This is given below:

HCl + NaOH —> NaCl + H2O

From the balanced equation above,

We obtained the following:

Mole ratio of the acid (nA) = 1

Mole ratio of base (nB) = 1

Next, we shall determine the volume of HCl needed for the reaction. This can be obtained as follow illustrated below:

MaVa / MbVb = nA/nB

2.5 x Va / 5 x 1.5 = 1

Cross multiply

2.5 x Va = 5 x 1.5

Divide both side by 2.5

Va = 5 x 1.5 / 2.5

Va = 3L

The volume of the acid required is 3L.

Finally, we shall convert the volume of the acid from litre (L) to millilitre (mL). This is illustrated below:

1L = 1000mL

Therefore, 3L = 3 x 1000 = 3000mL.

Therefore, the volume of the acid, HCl in mL needed fi4 the reaction is 3000mL

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