We take the derivative of Ohm's law with respect to time: V = IR
Using the product rule:
dV/dt = I(dR/dt) + R(dI/dt)
We are given that voltage is decreasing at 0.03 V/s, resistance is increasing at 0.04 ohm/s, resistance itself is 200 ohms, and current is 0.04 A. Substituting:
-0.03 V/s = (0.04 A)(0.04 ohm/s) + (200 ohms)(dI/dt)
dI/dt = -0.000158 = -1.58 x 10^-4 A/s
Answer:
The magnitude of the acceleration is 1.2 × 10⁴ mi/h²
Explanation:
Hi there!
The acceleration is defined as the change in velocity in a time:
a = Δv / Δt
Where:
a = acceleration.
Δv = change in velocity = final velocity - initial velocity.
Δt = elapsed time.
In this case:
Initial velocity = 60 mi/h
final velocity = 50 mi/h
elapsed time = 3.0 s
Let´s convert the time unit into h:
3.0 s · 1 h /3600 s = 1/1200 h
Now, let´s calculate the acceleration:
a = Δv / Δt
a = (50 mi/h - 60 mi/h) / 1/1200 h
a = -1.2 × 10⁴ mi/h²
The magnitude of the acceleration is 1.2 × 10⁴ mi/h²
PH measures the concentration of hydrogen ions (
) in a solution. Knowing this, you can determine how acidic -or basic- your solution is.
