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3 years ago

8

How does the abundance of hydrogen and helium support the Big Bang Theory?

2 answers:

Blababa [14]3 years ago

3 0

Answer:

Hydrogen and helium account for nearly all the nuclear matter in today's universe. This is consistent with the standard or "big bang" model. ... Basically , the hydrogen-helium abundance helps us to model the expansion rate of the early universe. If it had been faster, there would be more neutrons and more helium.

Explanation:

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Goshia [24]3 years ago

3 0

It is the proportion predicted to be present in the early universe.

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A 100 meter rope is 20 kg and is stretched with a tension of 20 newtons. If one end of the rope is vibrated with small amplitude

dezoksy [38]

Answer:

The velocity waves before rain is 10 m/s

The velocity of wave after the rope soaked up 5 kg more is 8.944 m/s

Solution:

As per the question:

Length of the rope, l = 100 m

Mass of the rope, m = 20 kg

Force due to tension in the rope, $T_{r} = 20 N$

Frequency of vibration in the rope, f = 10 Hz

Extra mass of the rope after being soaked in rain water, m' = 5 kg

Now,

In a rope, the wave velocity is given by:

$v_{w} = \sqrt{\frac{T_{r}}{M_{d}}}$ (1)

where

$M_{d}$ = mass density

Mass density before soaking, $M_{d} = \frac{m}{l} = \frac{20}{100} = 0.20$

Mass density after being soaked, $M_{d} = \frac{m + m'}{l} = \frac{25}{100} = 0.25$

Initially, the velocity is given by using eqn (1):

$v_{w} = \sqrt{\frac{20}{0.20}} = 10 m/s$

The velocity after being soaked in rain:

$v_{w} = \sqrt{\frac{20}{0.25}} = 8.944 m/s$

3 0

3 years ago

physics major is cooking breakfast when he notices that the frictional force between the steel spatula and the Dry Steel frying

givi [52]

Answer:0.667 N

Explanation:

Given

It is noticed that Frictional Force is 0.2 N

Coefficient of kinetic Friction $\mu _k=0.3$

We know Friction Force is given by

$f_r=\mu _k\times Normal\ reaction$

therefore

$0.2=\mu _k\times N$

$0.2=0.3\cdot N$

$N=\frac{0.2}{0.3}$

$N=0.667 N$

8 0

3 years ago

A 15.4 kg block is dragged over a rough, horizontal surface by a constant force of 182 N acting at an angle of 24◦ above the hor

Dima020 [189]

Answer:

Explanation:

Considering Work done by friction is asked

Given

mass of block $m=15.4\ kg$

force $F=182\ N$

inclination $\theta =24^{\circ}$

block is displaced by $s=57.6\ m$

coefficient of kinetic friction $\mu _k=0.135$

Friction force $F_r=\mu _kN$

Normal reaction $N=mg-F\sin \theta =15.4\times 9.8-182\sin (24)$

$N=76.9\ N$

Friction Force $F_r=0.135\times 76.9=10.38\ N$

Work done by friction force

$W=f_r\cdot s$

$W=10.38\times 57.6=597.92\ N$

3 0

3 years ago

Which is an example of the gravitational force?

Evgesh-ka [11]

1. A basketball was thrown in the air and falls to the ground

7 0

3 years ago

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A baseball with a mass of 0.80 kg is given an acceleration of 20.00 m/s. How much net force was applied to the ball

dybincka [34]

a x m = f

.80 x 20 = 16

4 0

3 years ago