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AnnZ [28]
2 years ago
14

Determine the mass of the object below to the correct degree of precision.

Physics
2 answers:
Vika [28.1K]2 years ago
4 0

Answer:

The correct degree of precision is 272.94 g.

Explanation:

Precision : It is defined as the closeness of two or more measurements to each other.

For Example: If you weigh a given substance five times and you get 2.7 kg each time. Then the measurement is said to be precise.

Level of precision is determined by the maximum number of decimal places.

In the given figure, the value of mass of object is 280 g. From the given options we conclude that the 272.94 g is more close to 280 g and has maximum number of decimal places. So, 272.94 g measurement is said to be precise.

Therefore, the correct degree of precision is 272.94 g.

Leviafan [203]2 years ago
3 0
272.94 is the answer
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Answer:

Explanation:

We shall apply concept of impulse to solve the problem  .

Impulse = force x time

impulse = change in momentum

force x time = change in momentum

initial speed u = 24 km/h = 6.67 m /s

final speed v = 65 km/h = 18.05 m /s

change in momentum = m v - mu

= m ( v-u )

= 1350 ( 18.05 - 6.67 )

= 15363 kg m/s

F x 18 = 15363

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What is the gravitational force on a 35.0 kg object standing on the Earth's surface?
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3 years ago
Quantum mechanics can be thought of as a ...
Mekhanik [1.2K]

Answer:

c. probablistic view of nature.

Explanation:

According to the problem of particle in a box in one dimension. If the particle energy E is taken less than the height of the barrier V.

Then with the help of classical mechanics it can be prove that the particle can not cross the barrier but according to the quantum mechanics, there is a small but a finite probability to cross the barrier.

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3 years ago
A car starts from rest with an acceleration of 2.84 m/s2 at the instant when a second car moving with a velocity of 25.7 m/s pas
vredina [299]

Answer:

464.69 m

Explanation:

First car

s=ut+\frac{1}{2}at^2\\\Rightarrow s=0\times t+\frac{1}{2}2.84t^2\\\Rightarrow s=1.42t^2

Second car

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\text{Distance}=25.7t

Here, the time taken and the distance traveled will be the same

Equating the two equations

1.42t^2=25.7t\\\Rightarrow t=\frac{25.7}{1.42}\\\Rightarrow t=18.09\ s

So, the first would have to move 1.42t^2=1.42\times 18.09^2=464.69\ m in order to overtake the second car.

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3 years ago
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