Answer:
Explanation:
There are different theories and evidence about the big bang, in this case, we're going to see three evidence.
The galaxies are moving from us, this means space is expanded, this in consequence Big Bang's explosion.
The cosmic microwave background radiation is related to the early warmth of the universe.
The observed abundance of hydrogen, helium, deuterium, lithium, these are checked from the spectra of the oldest stars.
Complete Question:
Metal sphere A has a charge of − Q . −Q. An identical metal sphere B has a charge of + 2 Q . +2Q. The magnitude of the electric force on sphere B due to sphere A is F . F. The magnitude of the electric force on sphere A due to sphere B must be:
A. 2F
B. F/4
C. F/2
D. F
E. 4F
Answer:
D.
Explanation:
If both spheres can be treated as point charges, they must obey the Coulomb's law, that can be written as follows (in magnitude):

As it can be seen, this force is proportional to the product of the charges, so it must be the same for both charges.
As this force obeys also the Newton's 3rd Law, we conclude that the magnitude of the electric force on sphere A due to sphere B, must be equal to the the magnitude of the force on the sphere B due to the sphere A, i.e., just F.
The statement about pointwise convergence follows because C is a complete metric space. If fn → f uniformly on S, then |fn(z) − fm(z)| ≤ |fn(z) − f(z)| + |f(z) − fm(z)|, hence {fn} is uniformly Cauchy. Conversely, if {fn} is uniformly Cauchy, it is pointwise Cauchy and therefore converges pointwise to a limit function f. If |fn(z)−fm(z)| ≤ ε for all n,m ≥ N and all z ∈ S, let m → ∞ to show that |fn(z)−f(z)|≤εforn≥N andallz∈S. Thusfn →f uniformlyonS.
2. This is immediate from (2.2.7).
3. We have f′(x) = (2/x3)e−1/x2 for x ̸= 0, and f′(0) = limh→0(1/h)e−1/h2 = 0. Since f(n)(x) is of the form pn(1/x)e−1/x2 for x ̸= 0, where pn is a polynomial, an induction argument shows that f(n)(0) = 0 for all n. If g is analytic on D(0,r) and g = f on (−r,r), then by (2.2.16), g(z) =
Answer:
The acceleration of the earth is 7.05 * 10^-25 m/s²
Explanation:
<u>Step 1:</u> Data given
mass of the apple = 0.43 kg
acceleration = 9.8 m/s²
mass of earth = 5.98 * 10 ^24 kg
<u>Step 2:</u> Calculate the acceleration of the earth
Following the third law of Newton F = m*a
F(apple) = F(earth) = m(apple)*a(apple)
F(apple) = 0.43 kg * 9.8 m/s² = 4.214 N
a(earth) = F(apple/earth)/m(earth)
a(earth) = 4.214N /5.98 * 10 ^24 kg
a(earth) = 7.05 * 10^-25 m/s²
The acceleration of the earth is 7.05 * 10^-25 m/s²