Answer:
The heat required is 1262.91 joules or 1.26 kilojoules.
Explanation:
The quantity of heat (Q) required to raise the temperature of a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)
Thus, Q = MCΦ
Since,
Q = ?
Mass of aluminum sample = 33.0g
C = 0.89 J/g℃
Φ = (Final temperature - Initial temperature)
= 68°C - 25°C = 43°C
Then, Q = MCΦ
Q = 33.0g x 0.89 J/g℃ x 43°C
Q = 1262.91 J
Since the heat in joules is 1262.91, obtain heat in kilojoules.
If 1000 joules = 1 kilojoules
1262.91 joules = Z
To get Z, cross multiply
Z x 1000 = 1262.91 x 1
1000Z = 1262.91
Z = 1262.91 / 1000
Z = 1.26291 kilojoules (when placed as 3 significant figures, Z is 1.26 kilojoules)
Thus, the heat required is 1262.91 joules or 1.26 kilojoules.
Answer: The correct option is 2.
Explanation: Group 15 elements are Nitrogen, phosphorous, Arsenic, Antimony, Bismuth.
To know whether an element exits as a diatomic molecule or not, we look at the atomicity of an element.
Atomicity is the number of atoms of an element combining to form a molecule.
Atomicity of Nitrogen = 2
Atomicity of Phosphorous = 4
Atomicity of Bismuth = 1
Atomicity of Arsenic = 1
The element having atomicity 2 will exist as a diatomic molecule.
Hence, Nitrogen is a diatomic molecule 
Assuming we have 100g, this means that
39.97g Carbon * 1 mol / 12 g = 3.33 mol Carbon
13.41g Hydrogen * 1 mol/1 g = 13.41 mol Hydrogen
46.62g Nitrogen * 1 mol / 14 g = 3.33 mol Nitrogen
Dividing everything by 3.33, we get
1 mol Carbon, 4.03 mol Hydrogen, 1 mol Nitrogen.
Empirical formula is CH4N
<span>The mass of the empirical formula is
12 + 4 + 14 = 30
Since the molar mass is double, we multiply all our subscripts
The molecular formula is C2H8N2
The answers to this question are </span><span>an empirical formula of CH4N</span> and a molecular formula of C2H8N2 .
Answer =Tsunamis because they flood places and areas
<u>We are given:</u>
Mass of NaCl in the given solution = 22.3 grams
Volume of the given solution = 2 L
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<u>Number of Moles of NaCl:</u>
We know that the number of moles = Given mass / Molar mass
Number of moles = 22.3 / 58.44 = 0.382 moles
<u></u>
<u>Molarity of NaCl in the Given solution:</u>
We know that Molarity of a solution = Moles of Solute / Volume of Solution(in L)
Molarity = 0.382 / 2
Molarity = 0.191 M
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