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Liono4ka [1.6K]
3 years ago
14

A string, 0.28 m long and vibrating in its third harmonic, excites an open pipe that is 0.82 m long into its second overtone res

onance. The speed of sound in air is 345 m/s. The speed of transverse waves on the string is closest to
Physics
1 answer:
Rama09 [41]3 years ago
7 0

Answer:

117.8 m/s

Explanation:

Given that:

String length, L = 0.28

pipe length, L' = 0.82

Speed of sound in air, v = 345 m/s

n = 3 (3rd harmonic)

Frequency, f of 3rd harmonic ;

f = (v*n) / 2L - - - - (1)

for the pipe: ; 3rd harmonic

f = (v*n) / 2L' - - - (2)

Equating (1) and (2)

(v*n) / 2L = (v*n) / 2L'

2L' * v * n = v* n * 2L

v = vL / L'

v = (345 * 0.28) / 0.82

v = 96.6 / 0.82

v = 117.80487

v = 117.8 m/s

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<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2>

\huge\boxed{OptionA}

<h2>_____________________________________</h2><h2>DATA:</h2><h3>Blue Car: </h3>

mass = 4 kg

velocity = 5 m/s^2

<h3 /><h3>Orange truck:</h3>

Mass= 2kg

Velocity = 7m/s^2

<h3 /><h3>Grey Car:</h3>

mass = 6 kg

velocity = 4m/s^2

<h3 /><h3>Green Car:</h3>

Mass = 8 kg

Velocity = 3 m/s^2

<h2>_____________________________________</h2><h2>SOLUTION:</h2>

By the equation of kinetic energy,

                                       

                                         K.E = \frac{1}{2} mv^2

Where,

            K.E is kinetic energy

            m is mass

            v is velocity

<h2>_____________________________________</h2><h3>Kinetic energy of Blue car:</h3>

 

Directly substitute the variables in the equation,

                                       

                                       K.E = \frac{1}{2}x4x5^2

Simplify the equation,

                                       K.E = 50 J

<h2>_____________________________________</h2><h3>Kinetic Energy of Silver Car:</h3>

                                           

 Directly substitude the variable in the equation,

                                                           

                                        K.E = \frac{1}{2}x6x4^2

Simplify the equation,

                                        K.E = 48J

<h2>_____________________________________</h2><h3>Kinetic Energy of Green Car:</h3><h3 />

Substitute the variables in the equation,

                                         

                                         K.E = \frac{1}{2}x8x3^2

Simplify the Equation,

                                         

                                         K.E = 36J

<h2>_____________________________________</h2><h3>Kinetic Energy of Orange Truck:</h3><h3 />

Substitute the variable,

                                        K.E = \frac{1}{2}x 2x7^2

Simplify the equation,

                                     

                                        K.E = 49J

<h2>_____________________________________</h2>

As you can see that the highest value of kinetic energy is of Blue SUV thus it will be out answer.

<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2><h3 /><h3 /><h3 /><h3 /><h2 /><h2 />
6 0
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