Mass of the object m = 2.9 kg
Force F1 = 28.449 N
F1 = m1 x a => a = F / m => 28.449 / 2.9 => a = 9.81, which is gravitational acceleration.
In the same lab, a = g = 9.81, second object F2 = 48.7N = m2 x a
m2 = F2 / a => 48.7 / 9.81 => m2 = 4.96 kg
Mass of the second object m2 = 4.96 kg
Answer:
Approximately 
(assuming that external forces on the cannon are negligible.)
Explanation:
If an object of mass 
is moving at a velocity of 
, the momentum 
of that object would be 
.
Momentum of the t-shirt:
.
If there is no external force (gravity, friction, etc.) on this cannon, the total momentum of this system should be conserved. In other words, if 
denote the momentum of this cannon:
.
.
Rewrite to obtain 
. Since the mass of this cannon is 
, the velocity of this cannon would be:
.
Yes.
The acceleration vector WILL point south when the car is slowing down while traveling north
