The answers are:
1. FALSE
2. FALSE
PART a)
As we know that weight is product of mass and gravity
so here we have
Part B)
Normal force is counter balanced by weight of the crate
so here we have
N = W = 127.4 N
PART C)
As we know that
F = ma
now we have
m = 13 kg
F = 40 N
now we have
Part D)
Maximum static friction force is given as
here we know that
now we have
PART E)
Since applied force on the block is
F = 12 N
Now since applied force is less than maximum static friction force
So it will not slide
So here friction force will be same as applied force
Static friction = 12 N
PART f)
Kinetic friction force is given as
here we know that
now friction force is
now we have
Part g)
as we know that
F = ma
Answer:
12.0 Volt
Explanation:
Step 1: Given data
Resistance of the ohmic dipole (R): 100 Ohm
Intensity of current (I): 120 mA (0.120 A)
Step 2: Calculate the voltage (V) across this chemical dipole
To calculate the voltage across the ohmic dipole, we will use Ohm's law.
I = V/R
V = I × R
V = 0.120 A × 100 Ohm = 12.0 V
A) produces offspring with variations