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Afina-wow [57]
3 years ago
10

A pendulum is raised 1.5 cm and allowed to fall. if air resistance is negligible, how high will the pendulum rise on the other s

ide?
Physics
2 answers:
padilas [110]3 years ago
6 0

Answer:

It will rise to same height (1.5 cm) on the other side of the pendulum.

Explanation:

When the pendulum moves, its kinetic energy is maximum at its mean position and potential energy is zero. While at both ends potential energy is maximum and the kinetic energy is minimum that is zero.

The energy is conserved during the process. So, if the friction is neglected, then there must be no loss of energy and the pendulum must rise to the same height on the other hand, as well. That is <u>1.5 cm</u>.

lions [1.4K]3 years ago
3 0
It should go to the same height if its not interacting with air
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The following is an example of how humans can increase biodiversity

Provide Wildlife Corridors and Connections Between Green Spaces

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You look at a barometer and see that the air pressure is getting much higher... How will the weather probably change? *
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How will the magnetic field of a straight wire carrying a constant current interact with the needle of a compass? Does the inter
Yuki888 [10]

Answer:

the needle will direct its North South according to the magnetic field of current carrying wire.

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Right hand rule tells the direction. Place the current carrying wire in your right hand with thumb pointing the direction of current. Curl of the fingers tell the direction of current.

When the needle gets in the vicinity of the field, its poles aligns itself with the field. (previous position of the compass needle has no effect on its position in the field). The north pole and south pole will be set in the direction of magnetic field.

The distance between the needle and wire does effect the strength (accuracy) of the needle position. Strong field will create strong deflection of the needle whereas when the distance from wire increases, field weakens, thus the deflection of needle will be weak.

5 0
3 years ago
A small metal bead, labeled A, has a charge of 28 nC .It is touched to metal bead B, initially neutral, so that the two beads sh
Dmitry_Shevchenko [17]

Answer:

Explanation:

Let the charge on bead A be q nC  and the charge on bead B be 28nC - qnC

Force F between them

4.8\times10^{-4} = \frac{9\times10^9\times q\times(28-q)\times10^{-18}}{(5\times10^{-2})^2}

=120 x 10⁻⁸ = 9 x q(28 - q ) x 10⁻⁹

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3 0
3 years ago
Please help me ; - ;
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Answer:

2 = C

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Explanation:

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