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siniylev [52]
3 years ago
9

If the reaction begins with 12.0 grams of O2 how many grams of NO2 will be produced given the following equation: 2 NO + O2 --&g

t; 2 NO2​
Chemistry
1 answer:
Brut [27]3 years ago
3 0

Answer:

69g

Explanation:

Given reaction expression:

             2NO  +  O₂ →2 NO₂

Unknown:

Mass of NO₂ produced  = ?

Solution:

To solve this problem, let us use the mole concept. We solve from the known to the unknown

In this regard, find the number of moles of O₂ given;

  Number of moles  = \frac{mass}{molar mass}  

Molar mass of O₂  = 2(16g/mol)  = 32g/mol

  Number of moles  = \frac{12}{16}   = 0.75mole

From the balanced reaction equation;

    1 mole of O₂ will produce 2mole of NO₂;

   0.75 mole of O₂ will produce 1.5mole of NO₂

Therefore, mass of NO₂;

  Mass of NO₂ = number of moles x molar mass

  Molar mass of NO₂ = 14 + 2(16) = 46g/mol

  Molar mass of NO₂ = 1.5 x 46  = 69g

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trapecia [35]

Answer:

157.64 L

Explanation:

We'll begin by converting 30 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

T(°C) = 30 °C

T(K) = 30 °C + 273

T (K) = 303 K

Next, we shall convert 600 mmHg to atm. This can be obtained as follow:

760 mmHg = 1 atm

Therefore,

600 mmHg = 600 mmHg × 1 atm / 760 mmHg

600 mmHg = 0.789 atm

Finally, we shall determine the volume of the gas. This can be obtained as follow:

Number of mole (n) = 5 moles

Temperature (T) = 303 K

Pressure (P) = 0.789 atm

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) =?

PV = nRT

0.789 × V = 5 × 0.0821 × 303

0.789 × V = 124.3815

Divide both side by 0.789

V = 124.3815 / 0.789

V = 157.64 L

Therefore, the volume of the gas is 157.64 L

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3. Weigh all the equipment and materials after the experiment.

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