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LekaFEV [45]
3 years ago
8

How does the loneliest whale relate to physics/waves.

Physics
1 answer:
Lelechka [254]3 years ago
6 0
Answer: the loneliest whale relates to the communication that whales give to each other

Explanation: whales have different forms of communication , and the ‘loneliest’ whale can’t get any company by the other whales.


In other words: it may be a new and different way whales communicate, nobody knows much about the loneliest whale. It may be forming a new kind of communication
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A 1.2 x 103 kg racecar, with a velocity of 8 m/s, collides with an unsuspecting 80 kg honey badger who is standing
aalyn [17]

Answer: 90 m/s

Explanation:

Given

mass of racecar M=1.2\times10^3\ kg

velocity of racecar u=8\ m/s

mass of still honeybadger m=80\ kg

after collision race car is traveling at a speed of v_1=2\ m/s

conserving linear momentum

Mu+m\times0=Mv_1+ mv_2\quad[v_2=\text{velocity of honeybadger after colllision}]

1.2\times10^3\times8+0=1.2\times10^3\times2+80\times v_2

1.2\times10^3(8-2)=80v_2\\v_2=\frac{7.2\times10^3}{80}=90\ m/s

4 0
3 years ago
The speed of water flowing through the 4in diameter section of the piping system is 3ft/s. What is the volume flow rate of water
olga_2 [115]
1 ft =12 in 
4 in = 0.333 ft 
volume = (п/4)*(0.333)² = 0.087 ft²
vol. flow = spead *volume
              =3 ft/s * 0.087 ft² 

vol flow = 0.261 ft³/s
3 0
3 years ago
What frequency is received by a person watching an oncoming ambulance moving at 110 km/h and emitting a steady 800-Hz sound from
Bas_tet [7]

Answer:

check photo for solve

Explanation:

7 0
3 years ago
Pls help my science teacher is a horrible teacher...
Anettt [7]

First of all, looks like your teacher is indeed pretty horrible. Secondly, the constraints to consider would be proper weight distribution, methods to minimize excessive motion of the building structure, and quantities such as volume and density, which would help in determining the optimal structure. Keeping the frequency of oscillation for a building low in case of an earthquake or natural disaster would also be a priority.

4 0
3 years ago
g A box having mass 0,5kg is placed in front of a 20 cm compressed spring. When the spring released, box having mass m1, collide
vagabundo [1.1K]

Answer:Expression given below

Explanation:

Given mass of spring\left ( m_1\right )=0.5 kg

Compression in the spring\left ( x\right )=20 cm

Let the spring constant be K

Using Energy conservation

potential energy stored in spring =Kinetic energy of Block\left ( m_1\right )

\frac{1}{2}Kx^2=\frac{1}{2}m_1v^2

v=x\sqrt{\frac{k}{m_1}}

now conserving momentum

m_1v=\left ( m_1+m_2\right )v_0

v_0=\frac{m_1}{m_1+m_2}v

where v_0 is the final velocity

3 0
3 years ago
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