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klemol [59]
3 years ago
12

Getting older means you should stop exercising

Physics
1 answer:
Morgarella [4.7K]3 years ago
8 0

Answer: False and Kinda true.

Explanation:If ya don't exercise your body will become weak and will die. same goes with old ppl. unless you are too old to exercise you can still take a walk. unless you have a wheel chair or no legs or a leg condition.

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An object is thrown vertically upward such that it has a speed of 25 m/s when it reaches two thirds of its maximum height above
AlekseyPX

Answer:

v0 = 25 m/s

vf = 0 m/s

a = -9.80 m/s^2

change in x = 31.89m

but that's only 1/3 of the hight, so i time it by 3 to get 96m

4 0
3 years ago
A car travels from Boston to Hartford in 4 hours. The two cities are 240 kilometers apart. What was the average speed of the car
Marat540 [252]
Speed=60. 240 divided by 4= 60k which is the total speed
3 0
3 years ago
Why do the positions of stars change in the universe?
leva [86]

If stars never changed, then constellations wouldn't change. But the stars, including the Sun, travel in their own separate orbits through the Milky Way galaxy. The stars move along with fantastic speeds, but they are so far away that it takes a long time for their motion to be visible to us.

6 0
3 years ago
A man walks 54.5 meters east, then another 30 meter east. Calculate his displacement relative to where he started.
Vedmedyk [2.9K]

d= d1+d2

d= 54.5+30=84.5

3 0
3 years ago
Electromagnetic radiation is emitted by accelerating charges. The rate at which energy is emitted from an accelerating charge th
statuscvo [17]

Answer:

 P /K = 1,997 10⁻³⁶  s⁻¹

Explanation:

For this exercise let's start by finding the radiation emitted from the accelerator

       \frac{dE}{dt} = \frac{q^{2} a^{2} }{6\pi  \epsilon_{o} c^{2}    }

the radius of the orbit is the radius of the accelerator a = r = 0.530 m

let's calculate

       \frac{dE}{dt} = [(1.6 10⁻¹⁹)² 0.530²] / [6π 8.85 10⁻¹² (3 108)³]

      P= \frac{dE}{dt}= 1.597 10⁻⁵⁴ W

Now let's reduce the kinetic energy to SI units

       K = 5.0 10⁶ eV (1.6 10⁻¹⁹ J / 1 eV) = 8.0 10⁻¹⁹ J

the fraction of energy emitted is

      P / K = 1.597 10⁻⁵⁴ / 8.0 10⁻¹⁹

      P /K = 1,997 10⁻³⁶  s⁻¹

3 0
3 years ago
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