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Rom4ik [11]
3 years ago
12

A life cycle assessment (LCA) determines the environmental impact at all stages of a product's life cycle, including production,

usage, and disposal;
the LCA process includes procedures that gather and evaluate the inputs and outputs of materials, energy, and the related impact that can be directly assigned to the product or process at any point in its life cycle;
the main purpose of an LCA is to assess potential environmental impact in order to address issues before hazardous or irreversible effects are created;
LCAs include goal definitions, inventories, impact analyses, and improvement analyses, which enable companies to identify environmental issues and explore possible solutions to problems; and
inherency is the property of a life cycle that may hide hazardous or energy-consuming processes, creating a net total product that appears to be benign or efficient but in actuality does have negative impacts.
Engineering
1 answer:
lisabon 2012 [21]3 years ago
4 0
Confusing very very confusing
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5 0
3 years ago
A compressor operates at steady state with Refrigerant 134a as the working fluid. The refrigerant enters at 0.24 MPa, 0°C, with
marissa [1.9K]

Answer:

POWER INPUT = 82.989 KW

Explanation:

For pressure P =0.24 MPa and T_1 = 0 DEGREE, Enthalapy _1 = 248.89 kJ/kg

For pressure P =1  MPa and T_1 = 50 DEGREE, Enthalapy _1 = 280.19 kJ/kg

Heat loss Q = 0.05w

Inlet diameter = 3 cm

exit diamter = 1.5  cm

volume of tank will be v = area * velocity

velocity at inlet= \frac{0.64\60 m/s}{ \frac{\pi}{4} (3\times 10^{-2})^2} = 15.09  m/s

velocity at outlet= \frac{0.64\60 m/s}{ \frac{\pi}{4} (1.5\times 10^{-2})^2} = 60.36  m/s

steady flow energy equation

E_{IN} = E_{OUT}

h_1 + \frac{v_1^2}{2g} +wc = h_2 + \frac{v_2^2}{2g} + 0.05wc

248.89 + \frac{15.09^2}{2} + wc = 280.18 + \frac{60.36^2}{2} + 0.05 wc

solving wc = 1830.64  kJ/kg

wc in KWH

we know thatwc = \dot m wc

       \dot m = 4.25 kg/m3 \times (0.64/60) m^3/s

\dot m = 0.04533  kg/s

wc = 0.04533 \times 1830.64 = 82.989 kW

5 0
4 years ago
Determine the COP of a refrigerator that removes heat from the food compartment at a rate of 5160 kJ/h for each kW of power it c
Mars2501 [29]

Answer:

COP_R=1.433\\Q_H=2.433kW

Explanation:

Hello,

In this case, the coefficient of performance of this refrigerator is defined in terms of the removed heat and the work input as:

COP_R=\frac{Q_{L}}{W_{in}} =\frac{5160\frac{kJ}{h}*\frac{1h}{3600s} }{1kJ/s} =1.433

Moreover, the rate of heat rejection to the outside air tuns out:

W_{in}=Q_H-Q_L\\Q_H=W_{in}+Q_L=1kW+5160\frac{kJ}{h}*\frac{1h}{3600s} =2.433kW

Best regards.

3 0
3 years ago
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A journeyman electrician with 16 years experience on-the-job was removing metal fish tape from a hole at the base of a metal lig
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3) Technicians and Electrical workers must be instructed to know the unsafe conditions associated with their work.

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5 0
3 years ago
C&A's potato chip filling process has a lower specification limit of 9.5 oz. and an upper specification limit of 10.5 oz. Th
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Answer:

Process capability index = (USL - LSL)/6Sigma = 1/6(0.3)= 0.56

Answer (a) 0.56

Explanation:

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4 years ago
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