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3 years ago

TIME REMAINING

Physics

2 answers:

lesya692 [45]3 years ago

7 0

Answer:

velocity and mass

Explanation:

Ber [7]3 years ago

3 0

Mass and velocity I think

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A train runs from New Delhi to Hyderabad it covers first of 420 km in 7 hours and the next distance of 360 km in 6 hours

Mkey [24]

Explanation:

the answer is 16.7 miles or 60kmph

5 0

3 years ago

Read 2 more answers

B. Assuming the acceleration is still -9.81 m/s2, what is the instantaneous velocity of the

goblinko [34]

We have that the instantaneous velocity of the shuttlecock when it hits the ground is

$V_{int}=\sqrt{U^2+19.6H}$

From the question we are told

Assuming the acceleration is still -9.81 m/s2, what is the instantaneous velocity of the

shuttlecock when it hits the ground? Show your work below.

Generally the equation for acceleration is mathematically given as

$a=v \frac{dv}{dx}\\\\\Therefore\\\\\2ah=v^2-u^2$

Where

acceleration is still -9.81 m/s2,

Hence,

$V^2-U^2=2(-9.81)*-H$

Therefore

$V_{int}=\sqrt{U^2+19.6H}$

For more information on this visit

brainly.com/question/12319416?referrer=searchResults

7 0

3 years ago

A 2.55 kg block starts from rest on a rough inclined plane that makes an angle of 60 degree with the horizontal. the coefficient

lorasvet [3.4K]

Answer:

Change in mechanical energy = work done by friction

so it is equal to

$W = -8.16 J$

Explanation:

As we know that change in mechanical energy must be equal to the work done by non conservative forces only

So here when block moves down the inclined plane then the work done by friction force is given as

$W = F.d$

here we have

$F = \mu F_n$

here we know that

$F_n = mg cos\theta$

so we have

$F_n = 2.55(9.81)(cos60)$

$F_n = 12.5 N$

Now the friction force on the block is given as

$F_f = \mu F_n$

$F_f = 0.25 \times 12.5$

$F_f = 3.13 N$

now work done by the friction is given as

$W = -(3.13)(2.61)$

$W = -8.16 J$

7 0

4 years ago

What happens when two waves meet while they travel through the same medium

Yuki888 [10]

Wave Interference or Interference of wave

7 0

4 years ago

If a 0.50-kg block initially at rest on a frictionless, horizontal surface is acted upon by a force of 3.7 N for a distance of 6

mel-nik [20]

The block's velocity is determined as 10.03 m/s.

<u>Explanation:</u>

According to work energy theorem, the work done on an object is equal to the change in kinetic energy of the object.

So, work done = Kinetic energy

$\text {Force } \times \text { displacement }=\frac{1}{2} \times m \times v^{2}$

Thus, the velocity can be determined as

$\text {velocity}=\sqrt{\frac{2 \times \text {Force} \times \text {displacement}}{m}}$

$\text {velocity}=\sqrt{\frac{2 \times 3.7 \times 6.8}{0.50}}=\sqrt{\frac{50.32}{0.50}}=\sqrt{100.64}$

Velocity = 10.03 m/s.

So the block's velocity is determined as 10.03 m/s.

5 0

4 years ago