Transmission of information in ANY form can be done digitally
or analoguely.
Beginning about 30 years ago, everything slowly started changing
to digital. Today, all commercial satellite communication, all optical
fiber communication, all internet communication, all computer
communication, all commercial cable communication, all commercial
television, and much of the telephone system, are all digital.
On your computer ... .pdf, .jpg, .mp3 etc. are all digital methods of
moving and storing information.
AM and FM radio are an interesting subject. They're all still analog.
They could easily be changed to all digital, and it would be a big
improvement, both for the broadcasters and for the listeners.
BUT ... every AM and FM radio that anybody has now would be
obsolete. Every single radio would either need to be replaced,
OR you'd need to add a digital decoder to every radio, like we
had to do with our TV sets a few years ago when television
suddenly became all digital. With AM and FM radios, the decoders
would be bigger, and would cost more, than most of the radios.
And that's why commercial radio broadcasting is still analog.
Increasing the tension of a spring affects a wave on the spring because it increases the frequency. When the tension rises, so does the frequency.
Answer:
a) Bullet will hit
b) Bullets will not hit
Explanation:
Given:
The velocity of the bullet, u = 
in the rest frame of the bullet pursuit car
The velocity of the original frame of reference, v = 
with respect to the pursuit car.
Now, according to the Galileo
the velocity of the bullet in the original frame of reference (u') will be
u' = u - v
on substituting the values we get
u' = 
or
u' = 
or
u' = 
since this velocity ( ) is greater than the ( 
)
hence,
<u>the bullet will hit</u>
Now, according to the Einstein theory
the velocity of the bullet in the original frame of reference (u') will be
on substituting the values we get
or
or
since,
is less than ( ), this means that the bullet will not hit
It will read the temperature of the atmosphere.It is unable to read the temperature of the sun because some of the heat energy from the sun is absorbed by the layer of air molecules on Earth.
Answer:
0.15A
Explanation:
The parameters given are;
R=20.0 Ω
C= 2.50 μF
V= 3.00 V
f= 2.48×10^-3 Hz
Xc= 1/2πFc
Xc= 1/2×3.142 × 2.48×10^-3 × 2.5 ×10^-6
Xc= 25666824.1
Z= 1/√(1/R)^2 +(1/Xc)^2
Z= 1/√[(1/20)^2 +(1/25666824.1)^2]
Z= 1/√(2.5×10^-3) + (1.5×10^-15)
Z= 20 Ω
But
V=IZ
Where;
V= voltage
I= current
Z= impedance
I= V/Z
I= 3.00/20
I= 0.15A
