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aleksandrvk [35]
2 years ago
8

You start with a container that is 8L big and the temperature in the room is 326K.

Chemistry
1 answer:
Ket [755]2 years ago
7 0

Answer:

The new volume is 8.64 L.

Explanation:

Charles's Law consists of the relationship that exists between the volume and the temperature of a certain quantity of ideal gas, which is maintained at a constant pressure. For a given sum of gas at constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases.

In summary, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the quotient that exists between the volume and the temperature will always have the same value:

\frac{V}{T} =k

Being an initial state 1 that modifies its conditions until a final state 2, it is fulfilled:

\frac{V1}{T1} =\frac{V2}{T2}

In this case:

  • V1= 8 L
  • T1= 326 K
  • V2= ?
  • T2= 352 K

Replacing:

\frac{8L}{326 K} =\frac{V2}{352 K}

Solving:

V2=352 K*\frac{8L}{326 K}

V2= 8.64 L

<u><em>The new volume is 8.64 L.</em></u>

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il63 [147K]
First write out the balanced equation. 3Cu+2Ag(NO3)3=2Ag+3Cu(NO3)2
Then convert copper from grams to moles
15 g*1 mol cu/63.54 g= 15/63.54 mol cu
Then use the mole ratio to convert Moles Cu to Moles Ag
15/63.54 moles Cu* 2 moles Ag/3 moles Cu
The final awnser is (15*2)/(63.54*3) moles Ag =0.157 moles Ag. If the question wants the answer in grams, convert from moles Ag to grams Ag.
0.157 moles Ag*107.87 g Ag/ mol Ag=16.98 g Ag
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C2h6o how many moles of ethanol are present in a 10.0 g sample of ethanol
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What do we call compounds that will not dissolve in water
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covalent compounds

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A balloon is filled to a volume of 1.6 L at 278 K. The balloon is left outside overnight and the temperature has dropped to 253
german

Explanation:

Charles' law gives the relationship between the volume and the temperature of the gas. Mathematically,

Volume ∝ Temperature

i.e. \dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}

We have, V₁ = 1.6 L, T₁ = 278 K, T₂ = 253, V₂=?

V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{1.6\times 253}{278}\\\\V_2=1.45\ L

So, the new volume is 1.45 L.

6 0
2 years ago
1.00 g of a compound is combusted in oxygen and found to give 3.14g of CO2 and 1.29 g of H2O. From these data we can tell thatA.
lora16 [44]

Answer:

the compound contains C, H, and some other element of unknownidentity, so we can’t calculate the empirical formula

Explanation:

Mass of CO2 obtained = 3.14 g

Hence number of moles of CO2 = 3.14g/44.0 g = 0.0714 mol

The mass of the carbon in the sample = 0.0714 mol × 12.0g/mol = 0.857 g

Mass of H2O obtained = 1.29 g

Hence number of moles of H2O = 1.29g/18.0 g = 0.0717 mol

The mass of the carbon in the sample = 0.0717 mol × 1g/mol = 0.0717 g

% by mass of carbon = 0.857/1 ×100 = 85.7 %

% by mass of hydrogen = 0.0717/1 × 100 = 7.17%

Mass of carbon and hydrogen = 85.7 + 7.17 = 92.87 %

Hence, there must be an unidentified element that accounts for (100 - 92.87) = 7.13% of the compound.

5 0
3 years ago
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