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aksik [14]
3 years ago
9

What are prevailing winds

Chemistry
1 answer:
Bad White [126]3 years ago
8 0

Answer:

a wind from the direction that is predominant at a particular place or season.

Explanation:

Brainlest is appriciated

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What occurs during a slump?
abruzzese [7]

Answer:

A slump is a form of mass wasting that occurs when a coherent mass of loosely consolidated materials or a rock layer moves a short distance down a slope.[1] Movement is characterized by sliding along a concave-upward or planar surface. Causes of slumping include earthquake shocks, thorough wetting, freezing and thawing, undercutting, and loading of a slope.

3 0
3 years ago
What causes the "heat island" effect?
Arada [10]
D all of the above answers are correct
6 0
3 years ago
Which statement describes a reason to consider air a mixture? A) The major constituents of air are gaseous elements. B) The comp
umka21 [38]

The correct answer is - A) The major constituents of air are gaseous elements.

With the statement ''the major constituents of air are gaseous elements'' we can easily conclude that the air is a mixture. The reason for that is that we have a plural usage of the word element, elements, which mean that there are multiple elements that make up the air.

The air is indeed predominantly a mixture of gaseous elements. The most abundant gas in the air being the nitrogen with 78.9%, oxygen with 20.95%, argon 0.93%, and carbon dioxide 0.04%, with lesser amounts of other gases also be present in it. The water vapor is also present in the air, though it is variable, being around 1% at sea level, but only 0.4% over the entire atmosphere.

3 0
4 years ago
Calculate the change in entropy if Br2(l) is converted to Br2(g).
Alik [6]

Ans: The entropy change for the given reaction is 93.3 J/K

Given reaction:

Br2(l) → Br2(g)

ΔS = ∑n(products)S⁰(products) - ∑n(reactants)S⁰(reactants)

     = 1 mole* S°(Br2(g)) - 1 mole*S°(Br2(l))

     =  1 mole *245.5 J/mol-K - 1 mole*152.2 J/mol-K

     = 93.3 J/K

5 0
3 years ago
Combustion analysis of a hydrocarbon produced 33.01 g co2 and 13.52 g h2o. calculate the empirical formula of the hydrocarbon.
Akimi4 [234]
Answer is: <span>the empirical formula of the hydrocarbon is CH</span>₂.<span>
Chemical reaction: C</span>ₓHₐ + O₂ → xC + a/2H₂O.<span>
m(CO</span>₂) = 33.01 g.
n(CO₂) = m(CO₂) ÷ M(CO₂).
n(CO₂) = 33.01 g ÷ 44.01 g/mol.
n(CO₂) = n(C) = 0.75 mol.
m(H₂O) = 13.52 g.
n(H₂O) = 13.52 g ÷ 18 g/mol.
n(H₂O) = 0.75 mol.
n(H) = 2 · n(H₂O) = 1.5 mol.
n(C) : n(H) = 0.75 mol : 1.5 mol /0.75 mol.
n(C) : n(H) = 1 : 2.

6 0
4 years ago
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