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lina2011 [118]
2 years ago
12

Please select the word from the list that best fits the definition growth from seed to plant

Chemistry
2 answers:
Misha Larkins [42]2 years ago
8 0
Is there a picture for this question ?
NeX [460]2 years ago
5 0

Answer:

kay, so u didn't gave the list but I guess I'm right...bcz of some words you wrote below..

yeah,

so your answer is <u>GERMINATION</u>

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What is the pH of a mixture of 0.042 M NaH2PO4 and 0.058 M Na2HPO4? Hint: The pKa of phosphate is 6.86.
AlekseyPX

Answer:

The pH value of the mixture will be 7.00

Explanation:

Mono and disodium hydrogen phosphate mixture act as a buffer to maintain pH value around 7. Henderson–Hasselbalch equation is used to determine the pH value of a buffer mixture, which is mathematically expressed as,

pH=pK_{a} + log(\frac{[Base]}{[Acid]})

According to the given conditions, the equation will become as follow

pH=pK_{a} + log(\frac{[Na_{2}HPO_{4} ]}{[NaH_{2}PO_{4}]})

The base and acid are assigned by observing the pKa values of both the compounds; smaller value means more acidic. NaH₂PO₄ has a pKa value of 6.86, while Na₂HPO₄ has a pKa value of 12.32 (not given, but it's a constant). Another more easy way is to the count the acidic hydrogen in the molecular formula; the compound with more acidic hydrogens will be assigned acidic and vice versa.

Placing all the given data we obtain,

pH=6.86 + log(\frac{0.058}{0.042})

pH=7.00

5 0
3 years ago
10mL volume of 75mM EtOH is necessary for an experiment. What volumes of 1M EtOH and water should be mixed to obtain the working
kenny6666 [7]

Answer: Volume of the 1M EtOH and water should be 0.75 ml and 9.25 ml respectively to obtain the working concentration.

Explanation:

According to the dilution law,

C_1V_1=C_2V_2

where,

C_1 = molarity of stock solution = 1M

V_1 = volume of stock solution = ?

C_2 = molarity of diluted solution = 0.075 M    (1mM=0.001M)

V_2 = volume of diluted solution = 10 ml

Putting in the values we get:

1M\times V_1=0.075M\times 10ml

V_1=0.75ml

Thus 0.75 ml of 1M EtOH is taken and (10-0.75)ml = 9.25 ml of water is added to make the volume 10ml.

Therefore, volume of the 1M EtOH and water should be 0.75 ml and 9.25 ml respectively to obtain the working concentration

3 0
3 years ago
Consider the following balanced equation. SiO2(s)+3C(s)→SiC(s)+2CO(g) Complete the following table, showing the appropriate numb
vlada-n [284]

Answer:

mol(SiO₂)              mol(C)               mol(SiC)                    mol(CO)

      3                          9                          3                                6

      1                           3                           1                                2

     13                         39                         13                             26

    2.5                        7.5                       2.5                            5.0

    1.4                         4.2                        1.4                            2.8

Explanation:

  • From the balanced equation:

<em>SiO₂(s) + 3C(s) → SiC(s) + 2CO(g),</em>

  • It is clear that 1.0 mole of SiO₂ reacts with 3.0 moles of C to produce 1.0 mole of SiC and 2.0 moles of CO.
  • We can complete the table of no. of moles of each component:

<u><em>1. 9.0 moles of C:</em></u>

We use the triple amount of C, so we multiply the others by 3.0.

So, it will be 3.0 moles of SiO₂ with 9.0 moles of C that produce 3.0 moles of SiC and 6.0 moles of CO.

<u><em>2. 1.0 mole of SiO₂:</em></u>

We use the same amount of SiO₂ as in the balnced equation, so the no. of moles of other components will be the same as in the balanced equation.

So, it will be 1.0 moles of SiO₂ with 3.0 moles of C that produce 1.0 moles of SiC and 2.0 moles of CO.

<u><em>3. 26.0 moles of CO:</em></u>

We use the amount of CO higher by 13 times than that in the balanced equation, so we multiply the others by 13.0.

So, it will be 13.0 moles of SiO₂ with 39.0 moles of C that produce 13.0 moles of SiC and 26.0 moles of CO.

<u><em>4. 7.5 moles of C:</em></u>

We use the amount of C higher by 2.5 times than that in the balanced equation, so we multiply the others by 2.5.

So, it will be 2.5 moles of SiO₂ with 7.5 moles of C that produce 2.5 moles of SiC and 5.0 moles of CO.

<u><em>5. 1.4 moles of SiO₂:</em></u>

We use the amount of SiO₂ higher by 1.4 times than that in the balanced equation, so we multiply the others by 1.4.

So, it will be 1.4 moles of SiO₂ with 4.2 moles of C that produce 1.4 moles of SiC and 2.8 moles of CO.

5 0
2 years ago
You are measuring the effects of salt on water's ability to freeze. To one of your water samples, you add sodium chloride (NaCl,
yulyashka [42]

Answer:

water

water is the worlds best solvent cause it can melt many different things also it is called the "Universal Solvent"

7 0
3 years ago
It is easier to determine the electron configurations for the p-block elements in periods 1, 2, and 3 than to determine the elec
babymother [125]

Answer:

Their electrons are placed in a higher number of orbitals

Explanation:

  • Suppose a element be Ga .

The atomic no is 31

The configuration is given by

\\ \sf\longmapsto 1s^22s^22p^63ss^23p^63d^{10}4s^24p^1

Or

\\ \sf\longmapsto [Ar]3d^{10}4s^24p^1

5 0
2 years ago
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