Darion bought a computer game for $22.50. It regularly

a store is having a clearance sale where merchandise on the sales racks is reduced by 80% from the original. if a jacket was ori

posledela

The sales price is $15.2

Step-by-step explanation:

Given,

Discount = 80%

Original price = $76

Discount price = 80% of original price

$Discount\ price=\frac{80}{100}*76\\Discount\ price=\frac{6080}{100}\\Discount\ price=\$60.8$

Sale's price = Original price - Discount price

$Sale\ price= 76-60.8\\Sale\ price= \$15.2$

The sales price is $15.2

Keywords: Subtraction, percentage

Learn more about subtraction at:

#LearnwithBrainly

8 0

4 years ago

1. Find the domain and range of the relation and determine whether it is a function.

Katyanochek1 [597]

A. the relation is a function

8 0

4 years ago

Match each series with the equivalent series written in sigma notation

PIT_PIT [208]

Answer:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

Step-by-step explanation:

Given

See attachment for complete question

Required

Match equivalent expressions

Solving (a):

$3 + 12 + 48 + 192 + 768$

The expression can be written as:

$3 \to 3*4^{0$ --- 0

$12 \to 3 * 4^{1$ ---- 1

$48 \to 3 * 4^{2$ --- 2

$192 \to 3 * 4^{3$ ---- 3

$768 \to 3 * 4^{4$ ---- 4

For the nth term, the expression is:

$Term = 3 * 4^{n$ ---- n

So, the summation is:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

Solving (b):

$4 + 32 + 256 + 2048 + 16384$

The expression can be written as:

$4 \to 4 * 8^0$ --- 0

$32 \to 4 * 8^1$ ---- 1

$256 \to 4 * 8^2$ --- 2

$2048 \to 4 * 8^3$ ---- 3

$16384 \to 4 * 8^4$ ---- 4

For the nth term, the expression is:

$Term \to 4 * 8^n$ ---- n

So, the summation is:

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

Solving (c):

$2 + 6 + 18 + 54 + 162$

The expression can be written as:

$2 \to 2 * 3^0$ --- 0

$6 \to 2 * 3^1$ ---- 1

$18 \to 2 * 3^2$ --- 2

$54 \to 2 * 3^3$ ---- 3

$162 \to 2 * 3^4$ ---- 4

For the nth term, the expression is:

$Term \to 2 * 3^n$ ---- n

So, the summation is:

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

Solving (d):

$3 + 15 + 75 + 375 + 1875$

The expression can be written as:

$3 \to 3 * 5^0$ --- 0

$15 \to 3 * 5^1$ ---- 1

$75 \to 3 * 5^2$ --- 2

$375 \to 3 * 5^3$ ---- 3

$1875 \to 3 * 5^4$ ---- 4

For the nth term, the expression is:

$Term \to 3 * 5^n$ ---- n

So, the summation is:

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

5 0

3 years ago

Help me plz it’s confusing

Alja [10]

X+8>= 18
therefore, the circle has to be on ten, (solid) and an arrow pointing to the right,
10+8>=18 which is true.

-7+x>= -8
the circle is going to be on -1, (solid) and pointing to the right.
-7 +-1 (-8) >=-8 which is true, then -7 +0>= -8 which is true
n-2<=4 so, the answer is a dot (solid) on 6 pointing to the left
6-2 (4) <=4 then 5-2 (3) <= 4 which both are true

-18+n<-7
so this answer is going to be on 10, and it will be a hollow dot, pointing to the left
-18+10 (-8) <-7 which is true
n-4>=13
so, this has to be greater than or equal to 13.
n must be greater than or equal to 17 (add 4 to both sides) so the dot (solid) is going to be on 17 and pointing to the right.

NOTICE: I had a different explanation for number 9, which is how I figured each one out.
Hope this helped! Sorry it took so long!

5 0

4 years ago

How many stamps that are 1.5 inches long and 1.5 inches wide will fit on a piece of paper that is 9 inches wide and one foot lon

Soloha48 [4]

Divide the paper which is 21 inches (12+9) by 1.5 and you have your answer which is 14

4 0

3 years ago