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Mariulka [41]
2 years ago
9

A brick and a feather fall to the earth at their respective terminal velocities. Which objectexperiences the greater force of ai

r friction?
Physics
1 answer:
Karo-lina-s [1.5K]2 years ago
4 0

Answer:

Under the reasonable assumption that the brick has more mass than the feather, the brick experiences a greater force of air friction.

Explanation:

<u>Objects at terminal velocity</u>, only under the influence of gravity, have maximized their speed and <u>have an acceleration of zero</u>.  Thus, neither object is accelerating.

Recall Newton's second law: \sum {\vec {F}}=m \vec {a}

Since acceleration for each object is zero, the sum of the force acting on each of those objects must also be zero.

Since the only forces acting on the objects are gravity and the force of air friction, in order to zero out, <u>the force of air friction must be equal in magnitude and opposite in direction to the force of gravity</u>.

Recall that near the surface of the earth, F_{gravity}=mg, so <u>the Force of Gravity acting on an object is directly proportional to the object's mass</u>.  <em>(A similar argument could be made even if this were not taking place on the surface of the earth, so long as the objects were the same distance from the object providing gravitational influence).</em>

If the masses of the objects are different, <u>the object with the greater mass will experience</u> a larger force of gravity, and hence <u>a larger force of air friction</u> at terminal velocity.  

Under the reasonable assumption that the brick has more mass than the feather, the brick experiences a greater force of air friction.

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Explanation:

Given that,

A student covered a distance of 210 meters in 35 seconds.

We need to find the student's speed in meters/second and also in meters/minute.

Speed, v = distance (d)/time (t)

So,

v=\dfrac{210\ m}{35\ s}\\\\=6\ m/s

We know that, 1 minute = 60 seconds

6\dfrac{m}{s}=6\times \dfrac{m}{(\dfrac{1}{60})\ \text{minutes}}\\\\=360\ \text{meters/minutes}

Hence, the student's speed is 6 m/s or 360 meters/minute.

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3 years ago
When you lift a book from the ground to your desk, what kind of work do you do negative or positive by lifting the book what do
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It would be kinetic energy. Let's say the book is weighs 10 Newtons you need to use a force of 10 Newtons to lift the book. In other words it's positive. As you move the book you're giving it energy. Namely potential energy which will turn to kinetic energy if you let it go. So you're changing it's position and energy.
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4 years ago
Hey guys, I have a question about heat and stuff, and converting. THINK YOU COULD HELP?! THANKS!
Alexxandr [17]

Before answering this question it is necessary to know the conversion factors for temperatures.

<em>273 k = 0 ° C </em>

To transform a temperature from Kelvin to ° C we use the following Formula

T ° C = T Kelvin - 273

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373K -273 = 100 ° C

<em>373 Kelvin equals 100° C. </em>

To transform a temperature from ° C to ° F we use the following formula:

(T° C x 9/5) + 32 = T ° F

Then:

<u>For 0 ° C </u>

(0° C x 9/5) +32 = 32 ° F

<em>0° C equals 32 ° F. </em>

<u>For 100° C </u>

(100 ° C x 9/5) +32 = 212 F

<em>100 ° C equals 212 ° F. </em>

Therefore, the correct option is the first:

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4 0
3 years ago
A solenoid having an inductance of 5.41 μH is connected in series with a 0.949 kΩ resistor. (a) If a 16.0 V battery is connected
vekshin1

Answer:

(A) 9.14\times 10^{-9}sec

(B) 6.20\times 10^{-3}A

Explanation:

We have given inductance L=5.41\mu H=5.41\times 10^{-6}H

Resistance R=0.949kohm=0.949\times 10^3ohm

Time constant of RL circuit is equal to \tau =\frac{L}{R}

\tau =\frac{5.41\times 10^{-6}}{0.949\times 10^3}=5.70\times 10^{-9}sec

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i=i_0(1-e^{\frac{-t}{\tau }})

According to question

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e^{\frac{-t}{\tau }}=0.201

{\frac{-t}{\tau }}=ln0.201

{\frac{-t}{5.7\times 10^{-9} }}=-1.6044

t=9.14\times 10^{-9}sec

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i=i_0(1-e^{\frac{-t}{\tau }})

i=\frac{16}{0.949\times 10^3}(1-e^{\frac{-\tau }{\tau }})

i=6.20\times 10^{-3}A

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Answer:

it is applicable on all bodies having mass and the bodies Will be governed by the same law

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