The balanced equation for formation of NH₃ is as follows;
N₂ + 3H₂ --> 2NH₃
Stoichiometry of N₂ to H₂ is 1:3
when gases react, stoichiometry of reactants applies to volumes as well.
Because 1 mol of any substance occupies 22.4 L at STP.
Therefore stoichiometry of volumes of N₂ to H₂ is 1:3
If N₂ is the limiting reactant,
1 L of N₂ reacts with 3 L of H₂
Therefore 20 L of N₂ should react with - 3/1 x 20 = 60 L
Only 25 L of H₂ is present therefore H₂ is the limiting reactant
ratio of H₂ to NH₃ is 3:2
if 3 L of H₂ forms - 2 L of NH₃
then 25 L of H₂ forms - 2/3 x 25 L = 16.67 L of ammonia
if 22.4 L of NH₃ contains 1 mol of NH₃
then 16.67 L of NH₃ consists of - 1/22.4 x 16.67 =0.74 mol oh NH₃
1 mol of NH₃ is made of 6.022 x 10²³ NH₃ molecules
Therefore 0.74 mol of NH₃ made of 6.022 x 10²³ molecules/mol x 0.74 mol
number of NH₃ molecules formed - 4.45 x 10²³ molecules of NH₃
N₂ is in excess
25 L of H₂ reacts with - 25/3 = 8.33 L
however 20 L present initially
Excess reactant left - 20 - 8.33 = 11.67 L of N₂ remaining
<span>during photosynthesis the co2 is converted into sugar
</span><span> 6 carbon compound that immediately splits into 2 molecules of 3-phosphoglycerate.
</span><span>3 CO2 + 9 ATP + 6 NADPH + 6 H+ → C3H6O3-phosphate + 9 ADP + 8Pi + 6 NADP+ + 3 H2O
</span>hope it helps
Answer:
Explanation:
According to the concept of “Like dissolves like”, the polar solutes dissolve in polar solvents, and non-polar solutes dissolve in non-polar solvents.
Covalent compounds which are formed by sharing of electrons between non metals, when dissolved in water, forms hydrogen bonding with water if they contain a electronegative atom along with hydrogen. Example: methanol
Ionic compounds which are made up of cations and anions, when dissolved in water, dissociate into ions. Example:
Thus equation which best represents methanol being dissolved in water is:
Answer:
0.00120 moles of electrons had traveled through the wire.
Explanation:
Amount current passed in 132 seconds = 0.880 A
Charge passed in 132 seconds = Q
Number of electrons = N
Magnitude of charge on an electron = q =
1 mole = ions/ particles/ atoms
The moles of electron in electrons:
0.00120 moles of electrons had traveled through the wire.