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matrenka [14]
2 years ago
7

The larger the amount of data collected,

Physics
2 answers:
Sedaia [141]2 years ago
7 0
I believe the answer would be False
Gala2k [10]2 years ago
7 0
I’m sure it’s false
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A tug-of-war game is played by five c/hildren: three on one team and two on the other. How much force will the two child team ha
dem82 [27]

Answer:

no, 3 porces is more tha 2 so the power between the 3 should be more than 2

Explanation:

4 0
3 years ago
Really confused on this. Any help will be great
pav-90 [236]
C is what i would go with
8 0
3 years ago
4. State in words how acceleration is calculated.
dimaraw [331]
You multiply force times friction
4 0
3 years ago
Beryllium has a charge of 2, and bromine has a charge of –1. which is the best name for the ionic bond that forms between them?
Otrada [13]

The best name for the ionic bond that forms between them is Beryllium Bromide.

We have been provided with data,

Beryllium charge, q = 2

Bromine charge, q = -1

As we know the valance electron of Be is +2  and the valance electron of bromine is -1. Since one is metallic and the other is non-metallic.

Now, when they combine they exchange valance electron, and bromine change into bromide so they form Beryllium Bromide.

So, the best name for the ionic bond that forms between them is Beryllium Bromide.  

Learn more about ionic bonds here:

brainly.com/question/21464719

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8 0
2 years ago
A 120-kg roller coaster cart is being tested on a new track, and a crash-test dummy is loaded into it. The roller coaster starts
avanturin [10]

Answer:

vb = 22.13 m/s

So, the only thing that was measured here was the height of point A relative to point B. And the Law of Conservation of Energy was used.

Explanation:

In order to find the speed of roller coaster at Point B, we will use the law of conservation of Energy. In this situation, the law of conservation of energy states that:

K.E at A + P.E at A = K.E at B + P.E at B

(1/2)mvₐ² + mghₐ = (1/2)m(vb)² + mg(hb)

(1/2)vₙ² + ghₐ = (1/2)(vb)² + g(hb)

where,

vₙ = velocity of roller coaster at point a = 0 m/s

hₙ = height of roller coaster at point a = 25 m

g = 9.8 m/s²

vb = velocity of roller coaster at point B = ?

hb = Height of Point B = 0 m (since, point is the reference point)

Therefore,

(1/2)(0 m/s)² + (9.8 m/s²)(25 m) = (1/2)(vb)² + (9.8 m/s²)(0 m)

245 m²/s² * 2 = vb²

vb = √(490 m²/s²)

<u>vb = 22.13 m/s</u>

<u>So, the only thing that was measured here was the height of point A relative to point B. And the Law of Conservation of Energy was used.</u>

5 0
3 years ago
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