All categories

3 years ago

How many moles are in 2.1 x 10^{24} molecules SiO4

Chemistry

1 answer:

lozanna [386]3 years ago

4 0

Answer: 3.5 moles

Explanation:

Based on Avogadro's law:

1 mole of any substance has 6.02 x 10^23 molecules

So, 1 mole of SiO4 = 6.02 x 10^23 molecules

Zmoles of SiO4 = 2.1 x 10^{24} molecules

To get the value of Z, cross multiply:

(2.1 x 10^{24} molecules x 1mole) = (6.02 x 10^23 molecules x Z moles)

2.1 x 10^{24} molecules = (6.02 x 10^23 x Z)

Z = (2.1 x 10^{24}) ➗ (6.02 x 10^23)

Z = 3.5 moles

Thus, there are 3.5 moles of SiO4.

You might be interested in

How many moles of ethylene (C2H4) can react with 12.9 liters of oxygen gas at 1.2 atmospheres and 297 Kelvin?

Inga [223]

So in this equation, 3 oxygen will react with 1 ethylene.
then, you convert from 12.9 Liters to moles.
1 mole = 22.4 Liters of gas.
x moles = 12.9 liters

So, 22.4x = 12.9, which means that x = 12.9/22.4, and you get about 0.6, then you divide by 3 because you have 3 Oxygen, and you get about 0.2.

So, 0.2 moles of ethylene C2H4 can react with 12.9 liters of Oxygen Gas.

Hope this Helps :)

3 0

3 years ago

A voltaic cell made of a Cr electrode in a solution of 1.0 M in Cr3+ and a gold electrode in a solution that is 1.0 M in Au3+.

Vikki [24]

Answer: a) Anode: $Cr\rightarrow Cr^{3+}+3e^-$

Cathode: $Au{3+}+3e^-\rightarrow Au$

b) Anode : Cr

Cathode : Au

c) $Au^{3+}+Cr\rightarrow Au+Cr^{3+}$

d) $E_{cell}=2.14V$

Explanation: -

a) The element Cr with negative reduction potential will lose electrons undergo oxidation and thus act as anode.The element Au with positive reduction potential will gain electrons undergo reduction and thus acts as cathode.

At cathode: $Au{3+}+3e^-\rightarrow Au$

At anode: $Cr\rightarrow Cr^{3+}+3e^-$

b) At cathode which is a positive terminal, reduction occurs which is gain of electrons.

At anode which is a negative terminal, oxidation occurs which is loss of electrons.

Gold acts as cathode ad Chromium acts as anode.

c) Overall balanced equation:

At cathode: $Au{3+}+3e^-\rightarrow Au$ (1)

At anode: $Cr\rightarrow Cr^{3+}+3e^-$ (2)

Adding (1) and (2)

$Au^{3+}+Cr\rightarrow Au+Cr^{3+}$

d) $E^0_(Cr^{3+}/Cr)$ = -0.74 V

$E^0_(Au^{3+}/Au)$ = 1.40 V

$E^0{cell}=E^0{cathode}-E^0{anode}=1.40-(-0.74)=2.14V$

Using Nernst equation :

$E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Au^{3+}]}{[Cr^{3+}]^}$

where,

n = number of electrons in oxidation-reduction reaction = 3

$E^o_{cell}$ = standard electrode potential = 2.14 V

$E_{cell}=2.14-\frac{0.0592}{3}\log \frac{[1.0}{[1.0]}$

$E_{cell}=2.14$

Thus the standard potential for an electrochemical cell with the cell reaction is 2.14 V.

6 0

4 years ago

In lewis structures, a solid line is used to represent...

sashaice [31]

Answer:

in lewis structure, a solid line is usually used to represent a bond between the atoms

Explanation:

the dots that are shown around the atom represent the valence electrons on the outer shell

when there are multiple atoms, either a pair of dots circled (one dot from each atom) or a solid line is used to show the bonds between those atoms

5 0

3 years ago

PLEASE HELP

AfilCa [17]

I think it’s salt water

7 0

3 years ago

Read 2 more answers

What is the total number of electrons in As-3?

V125BC [204]

Answer:

Arsenic, As, has atomic number 33, which is the number of protons in the nuclei of its atoms. A neutral As atom would also have 33 electrons. The electron configuration of a neutral arsenic atom is [Ar]3d104s24p3

Explanation:

5 0

3 years ago