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3 years ago

How many moles are in 2.1 x 10^{24} molecules SiO4

Chemistry

1 answer:

lozanna [386]3 years ago

4 0

Answer: 3.5 moles

Explanation:

Based on Avogadro's law:

1 mole of any substance has 6.02 x 10^23 molecules

So, 1 mole of SiO4 = 6.02 x 10^23 molecules

Zmoles of SiO4 = 2.1 x 10^{24} molecules

To get the value of Z, cross multiply:

(2.1 x 10^{24} molecules x 1mole) = (6.02 x 10^23 molecules x Z moles)

2.1 x 10^{24} molecules = (6.02 x 10^23 x Z)

Z = (2.1 x 10^{24}) ➗ (6.02 x 10^23)

Z = 3.5 moles

Thus, there are 3.5 moles of SiO4.

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3 years ago

Gallium is produced by the electrolysis of a solution made by dissolving gallium oxide in concentrated NaOH ( aq ) . Calculate t

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Answer:

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Explanation:

The gallium here is likely to be produced from a $\rm NaGaO_2\, (aq)$ solution using electrolysis. However, the problem did not provide a chemical equation for that process. How many electrons will it take to produce one mole of gallium?

Note the Roman Numeral " $\mathtt{(III)}$ " next to $\rm Ga$ . This numeral indicates that the oxidation state of the gallium in this solution is equal to $+3$ . In other words, each gallium atom is three electrons short from being neutral. It would take three electrons to reduce one of these atoms to its neutral, metallic state in the form of $\rm Ga\, (s)$ .

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How many electrons are supplied? Start by finding the charge on all the electrons in the unit coulomb. Make sure all values are in their standard units.

$t = \rm 80.0\; min = 80.0\; min \times 60\;s \cdot min^{-1} = 4800\; s$ .

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$\begin{aligned} n(\text{electrons}) &= \frac{Q}{F} \cr &= \rm \dfrac{1.824\times 10^3\; C}{96485.332\; C \cdot mol^{-1}}\cr &\approx \rm 1.89\times 10^{-2}\; mol \end{aligned}$ .

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