Answer:
V₂ = 1.48 L
Explanation:
Given data:
Initial volume = 1.23 L
Initial pressure = 755 mmHg (755/760 =0.99 atm)
Initial temperature = 0 °C (0 +273 = 273 K)
Final temperature = 50°C (50+273 = 323 K)
Final volume = ?
Final pressure = 0.97 atm
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 0.99 atm × 1.23 L × 323 K / 273 K × 0.97 atm
V₂ = 393.32 atm .L. K / 264.81 atm.K
V₂ = 1.48 L
Answer:
1.44 g
Explanation:
The problem gives you the molarity and volume of the target solution, so right from the start you know that you can use that information to determine the number of moles of hydrochloric acid that it must contain.
So, molarity measures a solution's concentration in terms of how many moles of solute, which in your case is hydrochloric acid, you get per liter of solution.
A
0.158 M
hydrochloric acid solution contains
0.158
moles of hydrochloric acid for very liter of solution. Since you're dealing with
250 mL
, the equivalent of
1
4
th
of a liter, your solution will contain
250
mL
⋅
1
L
10
3
mL
⋅
0.158 moles HCl
1
L
=
0.0395 moles HCl
Now that you know how many moles of hydrochloric acid are needed to prepare your solution, use the compound's molar mass to convert this to grams
0.0395
moles HCl
⋅
36.46 g
1
mole HCl
=
∣
∣
∣
∣
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
a
a
1.44 g
a
a
∣
∣
−−−−−−−−−−
Explanation:
Please brainliest.
Oxygen dichloride molecule consists of an oxygen atom and two chlorine atoms. According to the VSEPR theory, the 3-D shape of the compound is bent.
There are 6 valence electrons in the oxygen atom and each chlorine atom has 1 valence electrons. Therefore, there are 8 valence electrons or 4 pairs of valence electrons.
According to VSEPR theory, due repulsion between 4 pairs of valence electrons, bond angle between two O-Cl bonds becomes 110 degrees and the shape of the molecule of the compound becomes bent.
