Question

A red laser (740 nm) shines on a double slit (slit separation = 0.165 mm). What is the angle of the fourth order maximum (that is, the fourth bright fringe away from the central maximum)?

Answer 1

Answer:

The angle of the fourth order maximum is 1.027 degrees.

Explanation:

It is given that,

Wavelength of red laser, $\lambda=740\ nm=740\times 10^{-9}\ m$

Slit separation, $d=0.165\ mm= 0.000165\ m$

We need to find the angle of the fourth order maximum. For maximum, the equation is given by :

$d\ sin\theta=n\lambda$

$sin\theta=\dfrac{n\lambda}{d}$

$sin\theta=\dfrac{4\times 740\times 10^{-9}}{0.000165}$

$\theta=1.027^{\circ}$

So, the angle of the fourth order maximum is 1.027 degrees. Hence, this is the required solution.