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2 years ago

Why is protein classified as a polymer?

Chemistry

2 answers:

Anika [276]2 years ago

3 0

Its made up of a long chain of monomers so proteins are polymers made of amino acids I hope this helps! ^^;

Reil [10]2 years ago

3 0

Definitley a protine is counted as a polymer

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In the world of chemistry, a 'mole' is a number of something... a very large number of something.

kipiarov [429]

Given:

No of atoms present= 8.022 x 10^23 atoms

Now we know that 1 mole= 6.022 x 10^23 atoms

Hence number of moles present in 8.022 x 10^23 atoms is calculated as below.

Number of moles

= 8.022 x 10^23/6.022x 10^23

=1.3 moles.

Hence we have 1.3 moles present.

3 0

2 years ago

Determine the pH of the resulting solution if 25 mL of 0.400 M strychnine (C21H22N2O2) is added to 50 mL of 0.200 M HCl? Assume

DIA [1.3K]

Answer:

pH = 4.56

Explanation:

The strychnine reacts with HCl as follows:

C₂₁H₂₂N₂O₂ + HCl ⇄ C₂₁H₂₂N₂O₂H⁺ + Cl⁻

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For strychnine buffer:

pOH = 5.74 + log [C₂₁H₂₂N₂O₂H⁺] / [C₂₁H₂₂N₂O₂]

Initial moles of C₂₁H₂₂N₂O₂ are:

0.025L * (0.400 mol / L) = 0.01 moles C₂₁H₂₂N₂O₂

And of HCl are:

0.05L * (0.200 mol / L) = 0.01 moles HCl

That means after the reaction, you will have just 0.01 moles of C₂₁H₂₂N₂O₂H⁺ in 50mL + 25mL = 0.075L. And molarity is:

[C₂₁H₂₂N₂O₂H⁺] = 0.01 mol / 0.075L = 0.1333M

This conjugate acid, is in equilibrium with water as follows:

C₂₁H₂₂N₂O₂H⁺(aq) + H₂O(l) ⇄ C₂₁H₂₂N₂O₂ + H₃O⁺

<em />

<em>Where Ka = Kw / Kb = 1x10⁻¹⁴ / 1.8x10⁻⁶ = 5.556x10⁻⁹</em>

<em />

Ka is defined as:

Ka = 5.556x10⁻⁹ = [C₂₁H₂₂N₂O₂] [H₃O⁺] / [C₂₁H₂₂N₂O₂H⁺]

In equilibrium, concentrations are:

C₂₁H₂₂N₂O₂ = X

H₃O⁺ = X

C₂₁H₂₂N₂O₂H⁺ = 0.1333M - X

Replacing in Ka expression:

5.556x10⁻⁹ = [X] [X] / [0.1333M - X]

7.39x10⁻¹⁰ - 5.556x10⁻⁹X = X²

7.39x10⁻¹⁰ - 5.556x10⁻⁹X - X² = 0

Solving for X:

X = - 2.72x10⁻⁵M → False solution. There is no negative concentrations

X = 2.72x10⁻⁵M → Right solution.

As H₃O⁺ = X

H₃O⁺ = 2.72x10⁻⁵M

And pH = -log H₃O⁺

4 0

2 years ago

Pls help me with this

Olin [163]

CO2 goes on the bottom and O2 on the top.

5 0

2 years ago

Use the reaction and bond information to answer the question. H2 CO2 → CH2O2 Reactant bond energies: H–H is 432 kJ/mol, C=O is 7

Anna11 [10]

The energy absorbed by the system before the reaction start has been 752 kJ/mol.

The bond energy has been defined as the energy possessed by the bond that has been converted into the heat energy and utilized in the reaction.

The energy has been conserved in a chemical reaction. Thus, the energy absorbed by the reactant in the reaction has been the difference in the energy of the reactant and product.

<h3>Computation for the energy absorbed</h3><h3 />

The given reaction has been:

$\rm H_2\;+\;CO_2\;\rightarrow\;CH_2O_2$

The bond energy of the reactant has been:

H-H bond energy = 432 kJ/mol

2 C=O bond energy= 799 kJ/mol

The total energy of the reactant has been 432 kJ/mol + 799 kJ/mol

The total energy of the reactant has been 1231 kJ/mol

The bond energy of the product has been:

C-O bonds = 358 kJ/mol

C=O bonds = 745 kJ/mol

1 C-H bond = 413 kJ/mol

1 O-H bond = 467 kJ/mol

The total energy of the product has been 358 + 745 + 413 + 467 kJ/mol

The total energy of the product has been 1,983 kJ/mol

According to the law of conservation of energy:

$\text{Product energy=Reactant energy + energy absorbed}$

Substituting the values for energy absorbed:

$\text{1,983 kJ/mol=1231\;kJ/mol+ energy absorbed}\\\rm Energy\;absorbed=1983-1231\;kJ/mol\\Energy\;absorbed=752\;kJ/mol$

The energy absorbed by the system before the reaction start has been 752 kJ/mol.

Learn more about bond energy, here:

brainly.com/question/866298

7 0

1 year ago

Plz help due tomorrow what are the answers 1-5 will be marked brainliest

lina2011 [118]

1.)D

2.)B

3.)A

4.)C

5.)C

6 0

2 years ago