Question

A piston-cylinder device contains 0.05 m3 of saturated water liquid at 300 kPa.

Answer 1

Answer:

m = 50 kg

Explanation:

The mass of the liquid water inside the cylinder can be given by the following formula:

$\rho = \frac{m}{V}\\\\m = \rho V$

where,

m = mass of the liquid water inside the cylinder = ?

V = Volume of the liquid water inside the cylinder = 0.05 m³

ρ = Density of the liquid water = 1000 kg/m³

Therefore,

$m = (1000\ kg/m^3)(0.05\ m^3)$

m = 50 kg