<u>Answer:</u> The volume of stock solution needed is 0.016 L
<u>Explanation:</u>
To calculate the volume of stock solution, we use the equation:
where,
are the molarity and volume of the stock solution
are the molarity and volume of diluted solution
We are given:
Putting values in above equation, we get:
Hence, the volume of stock solution needed is 0.016 L
Means moving from one place to the other
Answer:
D) 0.50 mole of Ne
Explanation:
Given data:
Number of molecules of nitrogen = 3.0×10²³ molecules
Which sample contain same number of molecules as nitrogen= ?
Solution:
A) 0.25 mole of O₂
1 mole = 6.022×10²³ molecules
0.25 mol × 6.022×10²³ molecules / 1 mol
1.51×10²³ molecules
B) 2.0 moles of He.
1 mole = 6.022×10²³ molecules
2.0 mol × 6.022×10²³ molecules / 1 mol
12.044×10²³ molecules
C) 1.0 moles of H₂
1 mole = 6.022×10²³ molecules
D) 0.50 mole of Ne
1 mole = 6.022×10²³ molecules
0.50 mol × 6.022×10²³ molecules / 1 mol
3.0×10²³ molecules
Explanation:
No of molecules=0.500×6.023×10²³=3.011×10²³ molecules
True becuase dew is coming out of the air which if you look at a glass of water it has condensation on it becuase it is hot
