I believe that it most likely would be D.
That would be the NOBLE GASES (Helium, Neon, Argon, Krypton, Xenon, Radon). Because these elements have a filled outer shell (thus giving them the full octet that other elements crave), they are stable elements under normal circumstances and as such resist chemical combination.
Plz note that under special conditions, noble gases such as Xenon and Radon can form compounds (Xenon Fluoride and Oxide; Radon Fluoride)
Answer:
Explanation:
(KF)2(Al2O3)3(SiO2)6(H2O)
molecular formula
K₂F₂Al₆Si₆O₂₂H₂
2 x 39 + 2 x 19 + 6 x 27 + 6 x 28 + 22 x 16 + 2 x 2
= 78 + 38 + 162+ 168+ 352+ 4
= 802
Percentage of K = 78 x 100 / 802
= 9.72 %
Percentage of F = 38 x 100 / 802
= 4.74 %
Percentage of Al = 162 x 100 / 802
= 20.2 %
Percentage of Si = 168 x 100 / 802
= 20.9 %
Percentage of O = 352 x 100 / 802
= 43.9 %
Percentage of H = 4 x 100 / 802
= .54 %
First, you need to have a periodic table that contains the electronegativities values. once you have them, you just need to subtract the values of the atoms and each bond. I have attached a table with these values. also, it does not matter then order in which you subtract them because they are always positive values. even though you get negative values in your calculator, just make it positive.
H-S----> 2.1 - 2.5= 0.4
H-Cl---> 2.1 -3.0=0.9
H-O---> 2.1- 3.5= 1.4
H-F----> 2.1 - 4.0= 1.9
HF is the most polar because it has the highest electronegativity difference.
Copper(II) oxide or cupric oxide is the inorganic compound with the formula CuO. A black solid, it is one of the two stable oxides of copper, the other being Cu2O or cuprous oxide. As a mineral, it is known as tenorite. It is a product of copper mining and the precursor to many other copper-containing products and chemical compounds
