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Dimas [21]
3 years ago
8

Read the following sentences: “This substance on copper is green. It is called verdigris. Paola said, ‘In Spanish, the word for

green is verde.’”
Why does the author mention that the Spanish word for green is verde?
Chemistry
1 answer:
Pachacha [2.7K]3 years ago
4 0

Answer:

See below.

Step-by-step explanation:

The author is probably reminding us that knowing the origins of words helps us to remember what they mean.

If "verde" means "green", the "verd" in "verdigris" probably means that verdigris is green.

However, the "verd" in verdigris domes from other languages.

It was originally Latin "viride aeris" (green brass).

In old French it became "verte de Grèce" (green of Greece). The modern French spelling is "vert-de-gris" (green of grey).

The English word "verdigris" comes from the French words.

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3 years ago
Which has a higher mass percent of magnesium mgo or mg3n2?
vampirchik [111]
The  compound  that  has   higher  mass percent  is  Mg3N2  which is 72%


explanation
calculate  the %  mass  of Mg  in each  compound

%  composition  of  mg= molar mass of  Mg/  total  molar  mass  of the compound  x100

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3 years ago
How many grams are in 3.93 x 10^24 molecules of CCl4?
Lorico [155]
<h3>Answer:</h3>

1000 g CCl₄

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
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<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.93 × 10²⁴ molecules CCl₄

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of C - 12.01 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of CCl₄ - 12.01 + 4(35.45) = 153.81 g/mol

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 3.93 \cdot 10^{24} \ molecules \ CCl_4(\frac{1 \ mol CCl_4}{6.022 \cdot 10^{23} \ molecules \ CCl_4})(\frac{153.81 \ g \ CCl_4}{1 \ mol \ CCl_4})
  2. Multiply:                                                                                                             \displaystyle 1003.77 \ g \ CCl_4

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

1003.77 g CCl₄ ≈ 1000 g CCl₄

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