You’re answer would be B love!
The compound that has higher mass percent is Mg3N2 which is 72%
explanation
calculate the % mass of Mg in each compound
% composition of mg= molar mass of Mg/ total molar mass of the compound x100
in MgO = 24 /40 x100 = 60%
in Mg3N2 =72/100 x100 = 72 %
therefore the % composition in Mg3N2 is higher
<h3>
Answer:</h3>
1000 g CCl₄
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
3.93 × 10²⁴ molecules CCl₄
<u>Step 2: Identify Conversions</u>
Avogadro's Number
Molar Mass of C - 12.01 g/mol
Molar Mass of Cl - 35.45 g/mol
Molar Mass of CCl₄ - 12.01 + 4(35.45) = 153.81 g/mol
<u>Step 3: Convert</u>
- Set up:

- Multiply:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
1003.77 g CCl₄ ≈ 1000 g CCl₄
16000
is the answer
because I used the calculater
Answer:c
Explanation:
i think that what is was for me