Back in their laboratory, the team of scientists carefully measure the changes in density of a freshwater sample as they decreas
2 answers:
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The density of the block is 1.25 cm³
The correct answer to the question is Option B. 1.25 cm³
To solve this question, we'll begin by calculating the volume of the block. This can be obtained as follow:
Length = 7 cm
Height = 4 cm
Width = 3 cm
<h3>Volume =? </h3>Volume = Length × Width × Height
Volume = 7 × 3 × 4
<h3>Volume = 84 cm³</h3>Thus, the volume of the block is 84 cm³
Finally, we shall determine the density of the block. This can be obtained as follow:
Density is defined as mass per unit volume i.e
Mass of block = 105 g
Volume of block = 84 cm³
<h3>Density of block =? </h3>Therefore, the density of the block is 1.25 cm³.
Hence, Option B. 1.25 cm³ gives the correct answer to the question.
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Answer:
Explanation:
From the law of conservation of energy
Energy lost by the spring, W=Kinetic energy gained, KE+Potential energy gained, PE+Work done by friction, Fr
The required distance from A to B is
Answer:
Explanation:
Weight of the ladder is 355N
WL = 355N
The weight of the ladder acts at center of the ladder I.e at 4m from the bottom
Weight of firefighters is 870N
Wf = 870N
The fire fighter is at 6.3m from the bottom of the ladder.
N1 is the normal force exerted by the wall
N2 is the normal force exerted by the ground
Using Newton law
Check attachment
ΣFy = 0, since body is in equilibrium
N₂ - WL - Wf = 0
N₂ = WL + Wf
N₂ = 870 + 355
N₂ = 1225 N
This the normal force exerted by the ground on the wall.
Now to get N₁, let take moment about point A
So, before we take the moment we need to make sure that the forces are perpendicular to the plane(ladder), we need to resolve the weight of the ladder, firefighter and the normal of the wall to be perpendicular to the plane.
ΣMa = 0
Clockwise moment is equal to anti-clockwise moment
Moment Is the produce of force and perpendicular distance.
M = F×r
So,
WL•Cos50 × 4 + Wf•Cos50 × 6.3 —N₁•Sin50 × 8 = 0
355•Cos50 × 4 + 870•Cos50 × 6.3 =
N₁•Sin50 × 8
1825.52 + 3523.12 = 6.13N₁
6.13N₁ = 5348.64
N₁ = 5348.64/6.13
N₁ = 872.54 N.
The normal force exerted by the wall is 872.54N
