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yuradex [85]
2 years ago
15

Back in their laboratory, the team of scientists carefully measure the changes in density of a freshwater sample as they decreas

e its temperature from 20°C to 0°C. Based on the data in the table, what effect does decreasing the temperature from 20°C to 4°C have on the sample’s density?
Physics
2 answers:
BabaBlast [244]2 years ago
7 0

Answer: As the temperature of the water decreases from 20 degrees celsius to 4 degrees celsius, the density increases.

Explanation:

Y_Kistochka [10]2 years ago
5 0

The correct answer to this question would be.

As the temperature of the water decreases from 20°C to 4°C, the density increases.

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Light traveling in a medium of index of refraction n1 is incident on another medium having an index of refraction n2. Under whic
natta225 [31]

Answer:

Explanation:

Total internal reflections is a phenomenon where incident light rays when travelling from a denser medium or from a medium with higher refractive index to less dense medium or a medium  with lesser refractive index  ( The indices of refraction have the relation n₁ > n₂, where n₁ is the refractive index of the first medium and n₂ is the refractive index of medium 2) leads to the light ray being reflected back into the first medium instead of undergoing refraction. Usually, this occurs when the incident light rays angle to the normal is greater than a certain critical angle which is the angle when the refracted ray angle in the second medium is 90°

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3 years ago
A rock with a mass of 80grams dropped into a graduated cylinder with 30 ml of water in it the readingof water became 70 ml what
muminat

Explanation:

b = m \div v \\ 80 \div 30 \times 10 { -}^{2}

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3 years ago
Which biome is most likely to have animals that hibernate, or sleep for long periods during the winter to avoid the cold?
TiliK225 [7]
Either tundra or polar i think.
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3 years ago
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A hot air balloon is traveling vertically upward at a constant speed of 4.5 m/s. When it is 28 m above the ground, a package is
ella [17]

Answer:

1.97 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.8 m/s²

s=ut+\frac{1}{2}at^2\\\Rightarrow 21=4.5t+\frac{1}{2}\times -9.8\times t^2\\\Rightarrow 21=-4.5t-4.9t^2\\\Rightarrow 4.9t^2+4.5t-28=0\\\Rightarrow 49t^2+45t-280=0

Solving the above equation we get

t=\frac{-45+\sqrt{45^2-4\cdot \:49\left(-280\right)}}{2\cdot \:49}, \frac{-45-\sqrt{45^2-4\cdot \:49\left(-280\right)}}{2\cdot \:49}\\\Rightarrow t=1.97, -2.89

So, the time the package was in the air is 1.97 seconds

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3 years ago
Can somone pls help me??!! i’m very stuck
Alchen [17]

Answer:

its the third one

Explanation:

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3 years ago
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