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ratelena [41]
3 years ago
6

A car is traveling at 50 ft/s when the driver notices a stop sign 100 ft ahead and steps on the brake. Assuming that the deceler

ation due to braking is constant, what is the magnitude of the minimum deceleration for which the car would stop right at the stop sign?
Engineering
1 answer:
Naddika [18.5K]3 years ago
4 0

Answer:

minimum deceleration = 12.5 ft/s²

Explanation:

Data provided in the question:

Initial speed of the car, u  = 50 ft/s

Distance to cover, s = 100 ft

Final speed of the car = 0 ft/s             [ ∵ as the car stops ]

Now,

from the Newton's equation of motion

we have  

v² - u² = 2as

a is the acceleration

on substituting the respective values, we get

0² - 50² = 2 × a × 100

or

- 2500 = 200a

or

a = - 12.5 ft/s²

Here, the negative sign depicts the deceleration.

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Answer:

a) 70.29 %

b) 37%

Explanation:

percent reduction can be found from:

PR = 100*(π(do/2)^2-π(df/2)^2)/π(do/2)^2

     = 100*(π(11.34/2)^2-π(6.21/2)^2)/π(11.34/2)^2

     =70.29 %

percent elongation can be found from:

EL =L_f - Lo/Lo*100

    = (73.17 -53.3/53.3)*100

    = 37%

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Most business owners begin his business in order to increase profit and to expand.

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This refers to the various ways in which a business owner decides to organize his business and the policies which guides it.

With this in mind, we can see that Mr X believes that it is a good business practice to <em>prioritize the work</em> that seems the most difficult and the most likely to kill their projects but this is not a good business practice because it can put the entire business in jeopardy.

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7 0
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What would the Select lines need to be to send data for the fifth bit in an 8-bit system (S0 being the MSB and S2 being the LSB)
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For a turning operation, you have selected a high-speed steel (HSS) tool and turning a hot rolled free machining steel. Your dep
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Answer:

MRR = 1.984

Explanation:

Given that                              

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Diameter D= 1 in

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