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polet [3.4K]
3 years ago
9

There are 8 stages to work through in conflict resolution if one is to reach resolution.

Physics
1 answer:
Taya2010 [7]3 years ago
4 0

Answer:

true?

Explanation:

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In the formula Q = m × c ×Δ T, which symbol represents specific heat? c m Q Δ T
Licemer1 [7]

Answer:

C is your answer.

Explanation:

5 0
3 years ago
How much energy (in kj) do 3.0 moles of photons, all with a wavelength of 670 nm, contain? how much energy (in kj) do 3.0 moles
Kisachek [45]
1 mole of photons contain 6.023 \cdot 10^{23} photons (Avogadro number). This means that 3.0 moles of photons contain
N=3\cdot 6.023 \cdot 10^{23} =1.81 \cdot 10^{24} photons.

The wavelength of the light in the problem is \lambda=670 nm=670\cdot 10^{-9}m, so the frequency is
f= \frac{c}{\lambda}= \frac{3\cdot 10^8 m/s}{670 \cdot 10^{-9}m}=4.48 \cdot 10^{14}Hz

The energy carried by a single photon is
E=hf
where h=6.62 \cdot 10^{-34}Js is the Planck constant, while f is the frequency. Since this is the energy carried by a single photon, the energy carried by 3.0 moles of photons will be the energy of the single photon multiplied by the total number of photons:
E=Nhf=(1.81 \cdot 10^{24})(6.62 \cdot 10^{-34}Js)(4.48 \cdot 10^{14}Hz )=5.36 \cdot 10^5 J
which corresponds to E=536 kJ.
4 0
3 years ago
Which property of a filled balloon would be unchanged on the moon where there's no air and less gravity?
grigory [225]
Its mass, I suppose. Unless the balloon explodes.
3 0
4 years ago
What is the distance traveled by a vehicle in 12 minutes, if it’s speed is 35 km/h
Artemon [7]

Answer:

7 km

Explanation:

Okay so an hour is 60 mins, so

60/ 12 = 5

35/ 5 = 7

7 km

5 0
3 years ago
Read 2 more answers
Americium-241 is a radioactive substance used in smoke detectors. The half life of americium is 432 years. If a smoke detector i
romanna [79]

Answer:

0.5 g

Explanation:

The half-life of a radioactive isotope is the time it takes for a certain amount of that isotope to halve.

In this case, we have an isotope of Americium-241, which has a half-life of

\tau = 432 y

This means that after 1 half-life (432 years), there will be an amount of americium equal to half its initial amount.

In this problem, the initial amount of americium is

m_0 = 1 g

Therefore, after 432 years (1 half-life), the amount of americium left will be half:

m(432y) = \frac{m_0}{2}=0.5 g

7 0
3 years ago
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