There are 8 stages to work through in conflict resolution if one is to reach resolution.

A force of 100 newtons Is applled to a box at an angle of 36° with the horizontal. If the mass of the box Is 25 kilograms, what

faust18 [17]

Horizontal component of force = 100cos(36)= 80.9 N

5 0

3 years ago

Can you please answers these for me please today is the last day to turn in work and I need this to pass please I’m begging than

Ymorist [56]

Answer:

1. F = ma F = 0.2kg * 20m/s² = 4Kg * m/s² = 4N

2. F = ma F - 18Kg * 3m/s² = 54Kg * m/s² = 54N

3. F = ma F = 0.025Kg * 5m/s² = 0.125N

4. F = ma F = 50Kg * 4m/s² = 200N

5. F = ma F = 70Kg * 4m/s² = 280N

6. F = ma F = 9Kg * 9.8m/s² = 88.2N

Explanation:

Hope this helps ! ^^

8 0

2 years ago

A device that converts electrical energy into kinetic energy to turn an axle?

Advocard [28]

A motor is the devise

8 0

3 years ago

The Event Horizon Telescope needs a 22 micro-arcsecond resolution to view the event horizon regions around black holes. If the a

likoan [24]

Answer:

14869817.395 m

Explanation:

$\theta$ =22 microarcsecond

λ = Wavelength = 1.3 mm

Converting to radians we get

$22\times 10^{-6}\frac{\pi}{180\times 3600}\ radians$

From Rayleigh Criterion

$\theta=1.22\frac{\lambda}{D}\\\Rightarrow D=1.22\frac{\lambda}{\theta}\\\Rightarrow D=1.22\frac{1.3\times 10^{-3}}{22\times 10^{-6}\frac{\pi}{180\times 3600}}\\\Rightarrow D=14869817.395\ m$

Diameter of the effective primary objective is 14869817.395 m

It is not possible to build one telescope with a diameter of 14869817.395 m. But, we need this type of telescope. So, astronomers use an array of radio telescopes to achieve a virtual diameter in order to observe objects that are the size of supermassive black hole's event horizon.

7 0

3 years ago

Anna Litical and Noah Formula are experimenting with the effect of mass and net force upon the acceleration of a lab cart. They

timama [110]

Answer:

c. 48 cm/s/s

Explanation:

Anna Litical and Noah Formula are experimenting with the effect of mass and net force upon the acceleration of a lab cart. They determine that a net force of F causes a cart with a mass of M to accelerate at 48 cm/s/s. What is the acceleration value of a cart with a mass of 2M when acted upon by a net force of 2F?

from newtons second law of motion ,

which states that change in momentum is directly proportional to the force applied.

we can say that

f=m(v-u)/t

a=acceleration

t=time

v=final velocity

u=initial velocity

since a=(v-u)/t

f=m*a

force applied is F

m =mass of the object involved

a is the acceleration of the object involved

f=m*48.........................1

in the second case ;a mass of 2M when acted upon by a net force of 2F

f=ma

a=2F/2M

substituting equation 1

a=2(M*48)/2M

a=. 48 cm/s/s

6 0

3 years ago