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3 years ago

Suppose that 273 of a substance displaces 26ml of water what is the substance

1 answer:

3 0

273g/25 mL = 10.92 (that's the density)
What has a density of 10.92 grams/mL? I don't know but I bet it's in your notes or on the worksheet.

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According to periodic trend, which of the following most likely has the highest ionization energy? Na Al Si Ar

Minchanka [31]

electrons in the outer shell have the lowest ionization energy. (not even gonna consider the quantum model which does funny things with d-sublevel). Highest ionization energy in descending order is: Ar = 1520.6 Si = 786.5 Al = 577.44 Na 495.8

6 0

3 years ago

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Correct the incorrect reaction agno3(aq)+nacl(aq)→nacl(s)+agno3(aq) express your answer as a chemical equation. identify all of

Cloud [144]

I honestly do not know im sorry

6 0

3 years ago

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Ludmilka [50]

Answer:

Question 1 :

• A compound is ionic if it is made up of a metal or a cation (+) and a non metal or anion (-)

Question 2 :

• While naming ionic compounds, follow the formula → "metal" + "non-metal ending with ide "

• i.e; Sodium Chloride:

${ \rm{Na {}^{ + } _{(aq)} + Cl {}^{ - } _{(aq)} \: \dashrightarrow \: NaCl _{(aq)}} \: \: \: \: \: \: \: \: } \\ { \rm{sodium + chloride \: \dashrightarrow \: sodium \: chloride}}$

Question 3 :

• The answer above that question is perfect.

Question 4 :

1 atom → Mono. But it is highly recommended to ignore it

2 atoms → DI

3 atoms → TRI

4 atoms → TETRA

5 atoms → PENTA ( such as pentaoxide )

7 atoms → HEPTA ( such as heptaoxide )

Question 5 and 6:

Are perfectly answered.

5 0

3 years ago

If 18.0 mL of 0.800 M HCl solution are needed to neutralize 5.00 mL of a household ammonia solution, what is the molar concentra

k0ka [10]

Answer:

The molarity of ammonia will be 2.88 M.

Chemical equation

HCl + NH3 ------> NH4Cl

First of calculate the moles of HCl

mole of HCl = Molarity × Vol (L)

mole of HCl = 0.800× 0.018 = 0.014 mole

As the in balance chemical, moles of HCl and NH3 areequal

moles of NH3= 0.014

Molarity of NH3 = moles ÷ V(L) = 0.014/0.005 = 2.88 M

Result:

The molarity of ammonia will be 2.88 M.

3 0

3 years ago

How much tap water did you pour into each of the cups in Part A: Temperature of the lab?

Salsk061 [2.6K]

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7 0

3 years ago