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777dan777 [17]
3 years ago
5

Suppose that 273 of a substance displaces 26ml of water what is the substance

Chemistry
1 answer:
Llana [10]3 years ago
3 0
273g/25 mL = 10.92 (that's the density)
What has a density of 10.92 grams/mL?  I don't know but I bet it's in your notes or on the worksheet.
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n order to balance the following reaction S n+Cl 2→ S nCl 4, which coefficient should be inserted in front of chlorine?
victus00 [196]

Answer:

The coefficient that should be inserted in front of chlorine is 2

Explanation:

Sn  +  2Cl₂   →  SnCl₄

As we have 4 atoms of chlorine in product side, we need 4 Cl in reactant side.

Chlorine is a diatomic atom, so if we have 2 mol of it, we are having 4 atoms of Cl.

The law of conservation of mass must be respected in every chemical equation

4 0
3 years ago
Eddie is performing an experiment. He asked the question what type of soil makes plants grow the fastest. He has four plants. He
Bezzdna [24]
Manipulated variable: the types of soil
Responding variable: how much t the plants grow
4 0
3 years ago
List the following elements in order from lowest boiling point to highest
-BARSIC- [3]

Answer:

Aluminum lodide - 680 degrees

fructose- 824 degrees

potassium bromide- 2,615 degrees

calcium bromide 3, 515 degrees

lowest boiling point is 680 and highest is 3,515.

hope this helps:)

7 0
3 years ago
What is the predominant intermolecular force in CBr4
vovikov84 [41]
CBr4 is a symmetric tetrahedral molecule so it will be non-polar.
3 0
3 years ago
What is the molarity of a NaOH solution if 28.2 mL of a 0.355 M H2SO4 solution is required to neutralize a 25.0-mL sample of the
Verdich [7]

Answer:

[NaOH} = 0.4 M

Explanation:

In a reaction of neutralization, we determine the equivalence point of the titration. In this case, we have a strong base and a strong acid.

(H₂SO₄, is considered strong, but the first deprotonation is weak)

2NaOH  +  H₂SO₄  →  Na₂SO₄  + 2H₂O

As we have 2 protons in the acid, we need 2 OH⁻ from the base to form 2 molecules of water.

In the equivalence point we know mmoles of base = mmoles of acid

Let's finish the excersise with the formula

25 mL . M NaOH = 28.2 mL  .  0.355M

M NaOH = (28.2 mL  .  0.355M) / 25 mL → 0.400

8 0
3 years ago
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