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Stells [14]
2 years ago
5

A. What is the pH of a solution with a [H+] of 6.8 x 10^-11?

Chemistry
1 answer:
inysia [295]2 years ago
6 0

Answer:

[H+] = 6.8×10^-11

so, pH = - log[H+]

= - log [6.8×10^-11]

= -(-10.167)

= 10.167

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Answer:

See explanation

Explanation:

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7 0
3 years ago
The solubility of o2 at 20c is 1.38 x10^-3. the partial presure of o2 in the air at sea level is 0.27 atm. using henery;s law, c
netineya [11]

<u>Answer:</u> The solubility of oxygen at 682 torr is 4.58\times 10^{-3}M

<u>Explanation:</u>

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C_{A}=K_H\times p_{A}

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\frac{C_{1}}{C_{2}}=\frac{p_{1}}{p_2}

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C_1\text{ and }p_1 are the initial concentration and partial pressure of oxygen gas

C_2\text{ and }p_2 are the final concentration and partial pressure of oxygen gas

We are given:

Conversion factor used:  1 atm = 760 torr

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Putting values in above equation, we get:

\frac{1.38\times 10^{-3}}{C_2}=\frac{0.27atm}{0.897atm}\\\\C_2=\frac{1.38\times 10^{-3}\times 0.897atm}{0.27atm}=4.58\times 10^{-3}M

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