Answer:
1.070MKCl
Explanation:
So we know that the original formula is M= n/L (n being moles of solute, L being liters of solvent)
Since we do not have liters in this problem, we would need to convert milliliters to liters
<u>213 mL= 0.213 L</u>
We then see that we do not have moles, but we do have a mass, being <u>17.0 g.</u> we would need to convert these grams to moles, giving us <u>0.228 mol.</u>
Then, you would plug in <u>0.228 for your n</u>, and now you are ready to solve your original formula, plugging everything in.
M=n/L
M=0.228 mol/0.213L
M= 1.070MKCl
I know this was long, but I hope this helps (:
Answer:
41.66 mL of 12.0 M sulfuric acid are needed.
Explanation:
Concentration of sulfuric acid solution taken =
Volume of the 12.0 M Solution = 
Concentration of required solution = 
Volume of required 1.00 M solution = 
(Dilution)
41.66 mL of 12.0 M sulfuric acid are needed.
The freezing point and the boiling point of a solvent when a non-volatile solute is dissolved in it decrease and increase respectively.
True. Physical changes only affect the inter-molecular bonding and structure.
Hello!
First you have to find the molar mass of the molecules
C = 12
O = 16
2Cl = 71
6H2O = 108
Add them up to find the total molar mass
12 + 16 + 71 + 108 = 207g/mol
Divide the amount of water by the total molar mass
108 / 207 = 0.5217
Convert this to a decimal
0.5217 = 52.17%
The answer is 52.17%
Hope this helps!
