The answer would be 'First rocks formed on Earth'.
Answer:
<u>The car's fast. The ground isn't moving.</u>
Hope this helped! :D
Answer:
![x=1.75m](https://tex.z-dn.net/?f=x%3D1.75m)
Explanation:
From the exercise we have that
![y_{o}=1.3m\\v_{o}=3m/s, \beta =37\\](https://tex.z-dn.net/?f=y_%7Bo%7D%3D1.3m%5C%5Cv_%7Bo%7D%3D3m%2Fs%2C%20%5Cbeta%20%20%3D37%5C%5C)
<em><u>To find how far from the edge of the piano does the cat strike the floor, we need to calculate its time first </u></em>
![y=y_{o}+v_{oy}t+\frac{1}{2}gt^{2}](https://tex.z-dn.net/?f=y%3Dy_%7Bo%7D%2Bv_%7Boy%7Dt%2B%5Cfrac%7B1%7D%7B2%7Dgt%5E%7B2%7D)
At the end of the motion y=0m
![0=1.3+3sin(37)t-\frac{1}{2}(9.8)t^{2}](https://tex.z-dn.net/?f=0%3D1.3%2B3sin%2837%29t-%5Cfrac%7B1%7D%7B2%7D%289.8%29t%5E%7B2%7D)
Solving for t
or ![t=0.73s](https://tex.z-dn.net/?f=t%3D0.73s)
Since the <u>time</u> can't be negative the answer is t=0.73
Knowing that we can calculate how far does the cat strike the floor
![x=v_{ox}t=3cos(37)(0.73)=1.75m](https://tex.z-dn.net/?f=x%3Dv_%7Box%7Dt%3D3cos%2837%29%280.73%29%3D1.75m)
Answer:
242.85 Hz
Explanation:
For maximum intensity of sound, the path difference,ΔL = (n + 1/2)λ/2 where n = 0,1,2...
Since Abby is standing perpendicular to one speaker, the path length for the sound from the other speaker to him is L₁ = √(2.00² + 5.50²) = √(4.00 + 30.25) = √34.25 = 5.85 m.
The path difference to him is thus ΔL = 5.85 m - 5.50 m = 0.35 m.
Since ΔL = (n + 1/2)λ/2 and for lowest frequency n = 0,
ΔL = (n + 1/2)λ/2 = (0 + 1/2)λ/2 = λ/4
ΔL = λ = v/f and f = v/4ΔL where f = frequency of wave and v = velocity of sound wave = 340 m/s.
f = 340/(4 × 0.35) = 242.85 Hz