Answer:
i. n = 5
ii. ΔE = 7.61 × 
KJ/mole
Explanation:
1. ΔE = (1/λ) = -2.178 × 
(
- 
)
(1/434 × 
) = -2.178 × (
)
⇒ 434 × = (1/-2.178 × )
But, 
= 2
434 × = (1/2.178 × )
434 × × 2.178 × = 
⇒ 
= 5
Therefore, the initial energy level where transition occurred is from 5.
2. ΔE = hf
= (hc) ÷ λ
= (6.626 × 10−34 × 3.0 × 
) ÷ (434 × )
= (1.9878 × 
) ÷ (434 × )
= 4.58 × 
J
= 4.58 × 
KJ
But 1 mole = 6.02×
, then;
energy in KJ/mole = (4.58 × KJ) ÷ (6.02×)
= 7.61 × KJ/mole
Valleys i think !!! possibly
Answer:
If the electronegativity difference between bonded atoms are too much high ionic bonds are formed if the electronegativity diference is 0.4 or less than 0.4 non polar covalnet bond formed the difference greater than 0.4 polar covalent bond formed.
Explanation:
Ionic bond:
It is the bond which is formed by the transfer of electron from one atom to the atom of another element.
Both bonded atoms have very large electronegativity difference. The atom with large electronegativity value accept the electron from other with smaller value of electronegativity.
For example:
Sodium chloride is ionic compound. The electronegativity of chlorine is 3.16 and for sodium is 0.93. There is large difference is present. That's why electron from sodium is transfer to the chlorine. Sodium becomes positive and chlorine becomes negative ion.
Covalent bond:
It is formed by the sharing of electron pair between bonded atoms.
The atom with larger electronegativity attract the electron pair more towards it self and becomes partial negative while the other atom becomes partial positive.
For example:
In water the electronegativity of oxygen is 3.44 and hydrogen is 2.2. That's why electron pair attracted more towards oxygen, thus oxygen becomes partial negative and hydrogen becomes partial positive.
D. To answer this question refer to the periodic table and think logically about it. Adding one proton increases the atomic number so you go along the row to Nitrogen. If you lose one neutron then the atomic mass decreases by 1 so 14-1 is 13.
