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Phoenix [80]
3 years ago
12

When this candle is burned it seems to disappear over a period of time. In actuality, the candle is being converted to smoke,ash

, and carbon dioxide, and the energy is being released as heat and light. This is an example of _____________.
A. Murphy's law


B. the law of conservation of mass


C. the law of chemical reactions


D. the law of nature
Chemistry
1 answer:
Hitman42 [59]2 years ago
6 0
C.the law of chemical reactions
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People take antacids, such as milk of magnesia, to reduce the discomfort of acid stomach or heartburn. The recommended dose of m
Llana [10]

Answer:

V_{HCl}=0.208L=208mL

Explanation:

Hello,

In this case, since the chemical reaction is:

2HCl+Mg(OH)_2\rightarrow MgCl_2+2H_2O

We can see that hydrochloric acid and magnesium hydroxide are in a 2:1 mole ratio, which means that the neutralization point, we can write:

n_{HCl}=2*n_{Mg(OH)_2}

In such a way, the moles of magnesium hydroxide (molar mass 58.3 g/mol) in 500 mg are:

n_{Mg(OH)_2}=500mg*\frac{1g}{1000mg}*\frac{1mol}{58.3g}  =0.00858mol

Next, since the pH of hydrochloric acid is 1.25, the concentration of H⁺ as well as the acid (strong acid) is:

[H^+]=[HCl]=10^{-pH}=10^{-1.25}=0.0562M

Then, since the concentration and the volume define the moles, we can write:

[HCl]*V_{HCl}=2*n_{Mg(OH)_2}

Therefore, the neutralized volume turns out:

V_{HCl}=\frac{2*0.00858mol}{0.0562\frac{mol}{L} }\\ \\V_{HCl}=0.208L=208mL

Best regards.

3 0
3 years ago
An acid
tekilochka [14]
The answer is A. Has a low pH in solution.
5 0
3 years ago
Write the reaction of reduction of iron oxide (III).​
olga nikolaevna [1]

Answer: I don't know if this helps you or not, but this is from study.com:

I'm so sorry if it doesn't:

Explanation: Iron(III) oxide reacts with carbon monoxide according to the balanced equation:

Fe₂O₃ + 3CO ➡️ 2Fe + 3CO₂

A reaction mixture initially contains 23.00g Fe₂O₃ and 15.40g CO.

8 0
2 years ago
About 6 × 109 g of gold is thought to be dissolved in the oceans of the world. If the total volume of the oceans is 1.5 × 1021 L
Lelechka [254]

First, determine the number of moles of gold.

Number of moles  = \frac{given mass in g}{molar mass}

Given mass of gold  =6 \times 10^{9} g

Molar mass of gold  = 196.97 g/mol

Put the values,

Number of moles of gold  = \frac{6 \times 10^{9} g}{196.97 g/mol}

= 0.03046\times  10^{9} mole or 3.046\times  10^{7} moles

Now, molarity  = \frac{moles of solute}{volume of the solution in liters}

Put the values, volume of ocean  =1.5 \times 10^{21} L

Molarity = \frac{3.046\times 10^{7} moles}{1.5 \times 10^{21} L}

= 2.03\times 10^{-14} M

Thus, average molar concentration = 2.03\times 10^{-14} M




6 0
3 years ago
Formation of ionic bond is affected by​
Alina [70]

Answer:

Ionization energy, electronegativity, and lattice energy are the factors that influence the formation of ionic bonds of elements.

6 0
3 years ago
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