Answer:
Based on the properties electrically charged particles, we have that unlike charges attract and like charges repel each other. In order for proper application of an electrostatically negatively charged paint to be properly applied on the metal body surface of a vehicle, require that for attraction, the surface of the vehicle should be grounded and positively charged so as to effectively attract the negatively charged paint particles as it exits the nozzle, to form a strong attachment with the positively charged surface of the vehicle
Explanation:
Answer:
Because the planet is far away from the sun
Explanation:
The closer the planet is to the Sun, the greater the pull of the Sun's gravity, and the faster the planet orbits.
While, over here the Pluto is very far away from the Sun so it will have very little gravitational pull and still keeps revolving around the Sun
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Pls Mark Brainliest</em></u></h2>
The gravitational pull is weaker.
Answer:
ΔΦ = -3.39*10^-6
Explanation:
Given:-
- The given magnetic field strength B = 0.50 gauss
- The angle between earth magnetic field and garage floor ∅ = 20 °
- The loop is rotated by 90 degree.
- The radius of the coil r = 19 cm
Find:
calculate the change in the magnetic flux δφb, in wb, through one of the loops of the coil during the rotation.
Solution:
- The change on flux ΔΦ occurs due to change in angle θ of earth's magnetic field B and the normal to circular coil.
- The strength of magnetic field B and the are of the loop A remains constant. So we have:
Φ = B*A*cos(θ)
ΔΦ = B*A*( cos(θ_1) - cos(θ_2) )
- The initial angle θ_1 between the normal to the coil and B was:
θ_1 = 90° - ∅
θ_1 = 90° - 20° = 70°
The angle θ_2 after rotation between the normal to the coil and B was:
θ_2 = ∅
θ_2 = 20°
- Hence, the change in flux can be calculated:
ΔΦ = 0.5*10^-4*π*0.19*( cos(70) - cos(20) )
ΔΦ = -3.39*10^-6
This right here is an inelastic collision where kinetic energy is not conserved but still momentum is being conserved. We use momentum balance to solve. We do as follows:
m1v1 + m2v2 = (m1 + m2)v3
m1 = m2, v2 = 0
1000m1 = 2m1v3
v3 = 1000/2 = 500 m/s
Therefore, the final velocity of the two when they move off together would be 500 m/s.
