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fgiga [73]
3 years ago
9

What is the weight of a 2.00-kilogram object on

Physics
2 answers:
Stels [109]3 years ago
4 0

The answer is 19.6 N

Trava [24]3 years ago
3 0
<span>(4) 19.6 N</span>
On Earth's surface, a mass of 1kg <span>exerts a force(weight) of 9.81 N
So the weight= 9.81x2.00
                      =19.62N
                      =19.6N</span>
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What is the device used to detect and measure current?
dybincka [34]
The Ammeter is used to detect and measure current or amperage. Also a more common tool now used is a multimeter that detects and measures voltage, current, and resistance.

Any questions please just ask. Thank you.
6 0
3 years ago
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A container of soy milk has the instructions on its label to “shake well before opening ” The soy milk is most likely a ?
Elena-2011 [213]

Answer:

D. Suspension

4 0
3 years ago
It is correct to say that impulse is equal toA) momentum.B) the change in momentum.C) the force multiplied by the distance the f
goldenfox [79]

Answer:

B) the change in momentum

Explanation:

Impulse is defined as the product between the force exerted on an object (F) and the contact time (\Delta t)

I=F \Delta t

Using Newton's second law (F = ma), we can rewrite the force as product of mass (m) and acceleration (a):

I=(ma) \Delta t

However, the acceleration is the ratio between the change in velocity (\Delta v) and the contact time (\Delta t): a=\frac{\Delta v}{\Delta t}, so the previous equation becomes

I=m \frac{\Delta v}{\Delta t}\Delta t

And by simplifying \Delta t,

I=m \Delta v

which corresponds to the change in momentum of the object.

8 0
3 years ago
Saturn has an orbital period of 29.46 years. In two or more complete sentences, explain how to calculate the average distance fr
bixtya [17]
For astronomical objects, the time period can be calculated using:
T² = (4π²a³)/GM
where T is time in Earth years, a is distance in Astronomical units, M is solar mass (1 for the sun)
Thus,
T² = a³
a = ∛(29.46²)
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8 0
3 years ago
A 900-kg car cruising at a constant speed of 60 km/h is to accelerate to 100 km/h in 4 s. The additional power needed to achieve
kiruha [24]

To solve this problem we will apply the concepts related to power as a function of the change of energy with respect to time. But we will consider the energy in the body equivalent to kinetic energy. The change in said energy will be the difference between the two velocity data given by half of the mass. We will first convert the given units into an international system like this

Initial Velocity,

V_i = 60km/h (\frac{1000m}{1km})(\frac{1h}{3600s})

V_i = 16.6667m/s

Final Velocity,

V_f = 100km/h (\frac{1000m}{1km})(\frac{1h}{3600s})

V_f = 27.7778m/s

Now Power is defined as the change of Energy over the time,

P = \frac{E}{t}

But Energy is equal to Kinetic Energy,

P = \frac{\frac{1}{2} m\Delta v^2}{t}

P = \frac{\frac{1}{2} m(v_f^2-v_i^2)}{t}

Replacing,

P = \frac{\frac{1}{2} (900)(27.7778^2-16.6667^2)}{4}

P = 56kW

Therefore the correct answer is A.

8 0
3 years ago
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