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kumpel [21]
2 years ago
9

A copper rod takes up 75 mL of space. With a density of 8.96 g/mL, what is the mass of the rod

Chemistry
1 answer:
pantera1 [17]2 years ago
5 0
5.73 is the mass of the rod
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Fine the mole. 2.41 x 10^24 molecules CO2
vlada-n [284]

Answer:

<h2>4 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{2.41 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\  = 4.00322...

We have the final answer as

<h3>4 moles</h3>

Hope this helps you

5 0
3 years ago
Consider two different containers, each filled with 2 moles of Ne(g). One of the containers is rigid and has constant volume. Th
zysi [14]

Answer:

See explanation.

Explanation:

For the ideal gas law (PV = nRT), we can notice that when the temperatures increases, the pressure or the volume must increase.

For the container with constant volume, the pressure will increase. Because density is mass/volume, in this container the density will not change.

For the other container, the pressure must be the same as the external, so it will not change, then the volume must increase. When the volume increases, the density decreases (density = mass/volume), so the pressure doesn't change and the density decreases.

7 0
3 years ago
What can you infer about copper and silver based on the position related to each other on the periodic table
velikii [3]
They're metals and they are in the same group/family
8 0
3 years ago
Write an equation that shows the formation of a chromium(ii) ion from a neutral chromium atom.
daser333 [38]
The   equation  that  shows  the  formation  of  chromium (ii) ion  from  neutral  chromium  atom  is  as  follow
Cr ---> cr^2+   +  2e-
Cr^2+ is  the  chromium  ion   with  oxidation  state  of  two  which  is  one  of  the  common  ion  of  chromium.  Other  common  ion   of  chromium  include  chromium  of  oxidation  state  6  and  3

8 0
3 years ago
Read 2 more answers
Calculate the standard reaction enthalpy for the reaction NO2(g) → NO(g) + O(g) given +142.7 kJ/mol for the standard enthalpy of
bulgar [2K]

Answer:

The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.

Explanation:

O_2(g) \rightarrow \frac{2}{3}O_3(g),\Delta H^o_{1}=142.7 kJ/mol..[1]

O_2(g) \rightarrow 2 O(g),\Delta H^o_{2}=498.4 kJ/mol..[2]

NO(g) + O_3(g)\rightarrow NO_2(g) + O_2(g) ,\Delta H^o_{3} = -200 kJ/mol..[3]

NO_2(g)\rightarrow NO(g) + O(g),\Delta H^o_{4}=?..[4]

Using Hess's law:

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

2 × [4] = [2]- (3 ) × [1] - (2) × [3]

2\times \Delta H^o_{4}=\Delta H^o_{2} -3\times \Delta H^o_{1}-2\times \Delta H^o_{3}

2\times \Delta H^o_{4}=498.4 kJ/mol-3\times 142.7 kJ/mol-2\times -200 kJ/mol

2\times \Delta H^o_{4}=470.3 kJ/mol

\Delta H^o_{4}=\frac{470.3 kJ/mol}{2}=235.15 kJ/mol

The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.

7 0
3 years ago
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