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3 years ago

A man standing on the Earth can exert the same force with his legs as when he is standing

Physics

1 answer:

statuscvo [17]3 years ago

7 0

Answer:

Explanation:

From the analogy of the problem we are made to know that "a man standing on the earth can exert the same force with his legs as when he is standing on the moon".

This force he is exerting is due to his weight. If he can have the same weight on the earth and moon, therefore:

weight = mass x acceleration due gravity

His mass and acceleration due to gravity on both terrestrial bodies are the same.

So, his jump height will be the same on earth and on the moon.

In summary, we have been shown that his mass and the acceleration due to gravity on both planets are the same, therefore, his weight will also be the same. His jump height will also be same.

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A 58.1 kg wood board is resting on very smooth ice in the middle of a frozen lake. A 48.3 kg boy stands at one end of the board.

VLD [36.1K]

Answer:

V = 1.41 m /s

Explanation:

Movement in both wood board and boy is created by internal forces . No horizontal external force acts on them . So conservation of momentum will apply on both of them for movement in horizontal direction.

Mass of wood board x velocity = mass of boy x velocity

58.1 x V = 48.3 x 1.69

V = 1.41 m /s

4 0

4 years ago

How does moon changes position every day?

photoshop1234 [79]

It moves relative to the stars

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4 years ago

Explain how sociology will contribute to the understanding of daily life and what is happening within it?

Helen [10]

Answer:

Explain how sociology will contribute to the understanding of daily life and what is happening within it?

Sociology is the study of society of human being, how they develop and those things put in place for such development

Explanation:

Sociology helps to develop culture, how people interact with one another and this boost the relationship and development as far as human society is concerned.

8 0

3 years ago

Đun nóng đẳng áp 5 kmol khí, người ta đã truyền cho khí một nhiệt lượng 9,4.10^6 J và khi đó khí đã nóng thêm 400K. Tính công mà

gulaghasi [49]

Explanation:

Hi Linda,

How's it going?

Sorry I haven't been in touch for such a long time but I've had exams so I've been studying every free minute. Anyway, I'd love to hear all your news and I'm hoping we can get together soon to catch up. We just moved to a bigger flat so maybe you can come and visit one weekend?

How's the new job?

Looking forward to hearing from you!

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6 0

3 years ago

Two gliders move toward each other on a linear air track, which we assume is frictionless. Glider A has a mass of 0.50 kg, and g

Nataly_w [17]

Answer:

-0.4 m/s

-3.552 m/s

Explanation:

$m_1$ = Mass of first glider = 0.5 kg

$m_2$ = Mass of second glider = 0.3 kg

$u_1$ = Initial Velocity of first glider = 2 m/s

$u_2$ = Initial Velocity of second glider = -2 m/s

$v_1$ = Final Velocity of first glider

$v_2$ = Final Velocity of second glider = 2 m/s

As the linear momentum of the system is conserved we have

$m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\Rightarrow v_1=\dfrac{m_1u_1+m_2u_2-m_2v_2}{m_1}\\\Rightarrow v_1=\dfrac{0.5\times 2+0.3\times (-2)-0.3\times 2}{0.5}\\\Rightarrow v_1=-0.4\ m/s$

The velocity of glider A is -0.4 m/s

$u_1$ = 0

$u_2$ = -5 m/s

$v_2$ = 0.92 m/s

$m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\Rightarrow v_1=\dfrac{m_1u_1+m_2u_2-m_2v_2}{m_1}\\\Rightarrow v_1=\dfrac{0.5\times 0+0.3\times (-5)-0.3\times 0.92}{0.5}\\\Rightarrow v_1=-3.552\ m/s$

The velocity of glider A is -3.552 m/s

8 0

3 years ago