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Nina [5.8K]
3 years ago
9

Use appropriate units and significant figures.  USE THE LAW OF COSINES AND LAW OF SINES.

Physics
1 answer:
N76 [4]3 years ago
3 0

Answer:

The resultant velocity is 86.1 mi/h.    

Explanation:

The law of cosines is given by:

c^{2} = a^{2} + b^{2} - 2abcos(\theta)

Where:

c: is the resultant velocity =?

a: is the velocity of the plane = 75.0 mi/h

b: is the velocity of the wind = 15.0 mi/h  

θ: is the angle between "a" and "b"                          

The angle between "a" and "b" can be found as follows:

\theta = 180.0 - 46.0 = 134.0 ^{\circ}

Now, by using the law of cosines we have:

c^{2} = (75.0)^{2} + (15.0)^{2} - 2*75.0*15.0*cos(134.0) = 7413.0

c = 86.1 mi/h    

Therefore, the resultant velocity is 86.1 mi/h.    

The law of sines is:

\frac{a}{sin(\gamma)} = \frac{b}{sin(\alpha)} = \frac{c}{sin(\theta)}

Where:

γ: is the angle between "b" and "c"

α: is the angle between "a" and "c"

So, if we want to find "c" by using the law of sines, we need to know another angle besides θ (γ or α), and the statement does not give us.

I hope it helps you!        

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A beam of 1.0 MHz ultrasound begins with an intensity of 1000 W/m². After traveling 12 cm through tissue with no significant ref
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Answer:

Option C

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Given:

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- attenuation coefficient soft tissue a = 0.54

Find:

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Solution

- The amount of attenuation in (dB) with the progression of depth is given by:

                                     Attenuation = a*f*d

                                     Attenuation = 0.54*12*1

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- The relation with attenuation and ratio of input and output intensity is given by:

                                     Attenuation = 10*log_10 (I_i / I_o)

                                     6.48 dB = 10*log_10 (I_i / I_o)

                                      I_i / I_o = 10^(0.648)

                                      I_o = 1000 / 10^(0.648)

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Answer:

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