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patriot [66]
3 years ago
14

"A bicycle's brakes apply 299 N of frictional force to the wheels as the bike moves 24 m

Chemistry
1 answer:
Usimov [2.4K]3 years ago
8 0

Answer:

0.62 N

Explanation:

first of all: 3.0 s = 0.05 m

Let ? be the work that brakes do at 3.0s

24 m ----> 299 N

0.05 m ---->?

? = (0.05 m x 299 N)/ 24

? = (14.95)/ 24

? = 0.622 N

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Answer:

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