Answer:
17.1195 grams of nitric acid are produced.
Explanation:

Moles of nitrogen dioxide :

According to reaction 3 moles of nitrogen dioxides gives 2 moles of nitric acid.
Then 0.5434 moles of nitrogen dioxides will give:
of nitric acid.
Mass of 0.3623 moles of nitric acid :

Theoretical yield = 22.8260 g
Experimental yield = ?


Experimental yield of nitric acid = 17.1195 g
Answer:
2.5×10^-7mol/dm^3
Explanation:
Firstly convert the cm^3 to dm^3
200×1000=200000dm^3
Calculate the g/dm^3
2/200000=0.00001g/dm^3
To calculate mol/dm^3
Mol/dm^3=mass given\molar mass
=0.00001/40
=2.5×10^-7mol/dm^3
Density is the measure of a mass per unit volume of a material substance
density= Mass/volume
The unit of density is g/cm^3
M=(mols/L) so M=(9.0/2.5) which is 3.6M
We have to know final temperature of the gas after it has done 2.40 X 10³ Joule of work.
The final temperature is: 75.11 °C.
The work done at constant pressure, W=nR(T₂-T₁)
n= number of moles of gases=6 (Given), R=Molar gas constant, T₂= Final temperature in Kelvin, T₁= Initial temperature in Kelvin =27°C or 300 K (Given).
W=2.4 × 10³ Joule (Given)
From the expression,
(T₂-T₁)=
(T₂-T₁)= 
(T₂-T₁)= 48.11
T₂=300+48.11=348.11 K= 75.11 °C
Final temperature is 75.11 °C.