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4 years ago

Please answer the question below

Physics

1 answer:

scoundrel [369]4 years ago

6 0

The correct answer is B.
In a velocity vs time graph, a line going up means an increase in velocity, or speed, which correlates to positive acceleration. Negative acceleration means slowing down.

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If it requires 7.0 J of work to stretch a particular spring by 1.8 cm from its equilibrium length, how much more work will be re

belka [17]

Answer:

56 J

Explanation:

The following data were obtained from the question:

Energy 1 (E₁) = 7 J

Extention 1 (e₁) = 1.8 cm

Extention 2 (e₂) = 1.8 + 3.6 = 5.4 cm

Energy 2 (E₂) =?

Energy stored in a spring is given by the following equation:

E = ke²

Where E is the energy.

K is the spring constant.

e is the extension.

E = ke²

Divide both side by e²

K = E/e²

Thus,

E₁/e₁² = E₂/e₂²

7/ 1.8² = E₂/ 5.4²

7 / 3.24 = E₂/ 29.16

Cross multiply

3.24 × E₂ = 7 × 29.16

3.24 × E₂ = 204.12

Divide both side by 3.24

E₂ = 204.12 / 3.24

E₂ = 63 J

Thus, the additional energy required can be obtained as follow:

Energy 1 (E₁) = 7 J

Energy 2 (E₂) = 63 J

Additional energy = 63 – 7

Additional energy = 56 J

8 0

3 years ago

When a guitar is tuned to adjust it pitch what is it that is changed?

suter [353]

Answer:

B) Its frequency

Explanation:

<u>The pitch of sound heard depends on its frequency of the sound wave. Frequency refers to how fast the sound wave is oscillating. </u>
A high frequency sound wave has a high pitch while a low frequency sound wave has a low pitch.
The faster the sound wave oscillates the higher the pitch. For instance, a guitar with a big heavy string will vibrate slowly and thus create a low pitch.

3 0

3 years ago

Electric power is to be generated by installing a hydraulic turbine-generator at a site 120 m below the free surface of a large

iogann1982 [59]

Answer:

P = 2234400 Watt

Explanation:

Power generation is given as rate of work done

Here the turbine generator is located at 120 m below the free surface

So here rate of work done is given as rate of potential energy

$Power = \frac{dw}{dt}$