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nadya68 [22]
4 years ago
8

Please answer the question below

Physics
1 answer:
scoundrel [369]4 years ago
6 0
The correct answer is B.
In a velocity vs time graph, a line going up means an increase in velocity, or speed, which correlates to positive acceleration. Negative acceleration means slowing down.
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When the photosphere is covered, the corona, chromospheres, and prominences are visible.
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This true it will be visible if they are covered
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What would increase the force of gravity between two objects?
yulyashka [42]
By Newton's Law of Universal Gravitation.

F =  GMm/r²

Where F is Force of Gravitation, M = Mass of first object, m = mass of second object, r = distance of separation

From the formula, you can see that if the masses, M and m, increased, the value of F would definitely increase as well.

And if r increased the value of F would be reduced because you would be dividing by a bigger number, but when the value of r is decreased the value of F would be increased, because you would then be dividing by something smaller. Note the r is at the denominator of the formula.

So F would increase if there was increase in Masses and decrease in distance.

So the answer is C. a and b.
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3 years ago
Write each of Newton's three laws of motion. Use your own wording.
12345 [234]

Answer:

In the first law ,an object will not change its motion unless a force acts on it. In the second law force on an object is equal to its mass times its acceleration. In the third law ,when two objects interact , they apply forces to each other of equal magnitude and opposite direction

5 0
3 years ago
A particular wave can be described as transverse and self-propagating. What type of wave could it be?
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6 0
4 years ago
Read 2 more answers
The height (in meters) of a projectile shot vertically upward from a point 2 m above ground level with an initial velocity of 25
Ivanshal [37]

Answer:

a) v(2\,s) = 5.9\,\frac{m}{s}, v(4\,s) = -13.7\,\frac{m}{s}, b) t = 2.602\,s, c) h(2.602\,s) = 35.176\,m, d) t = 5.281\,s, e) v(2.602\,s) = -26.254\,\frac{m}{s}

Explanation:

a) The velocity function is determined by deriving the position function in time:

v(t) = 25.5-9.8\cdot t

Velocities after 2 seconds and 4 seconds are, respectively:

v(2\,s) = 5.9\,\frac{m}{s}

v(4\,s) = -13.7\,\frac{m}{s}

b) The maximum height is reached when velocity is equal to zero:

25.5-9.8\cdot t = 0

The time when the projectile reaches the maximum height:

t = 2.602\,s

c) The maximum height is:

h (2.602\,s) = 2 + 25.5\cdot (2.602\,s)-4.9\cdot (2.602\,s)^{2}

h(2.602\,s) = 35.176\,m

d) The projectile hits the ground when height is equal to zero:

-4.9\cdot t^{2}+25.5\cdot t + 2 =0

The roots of the second order polynomial are presented below:

t_{1} \approx 5.281\,s

t_{2} \approx -0.077\,s

The first one is the only reasonable solution in physical terms.

t = 5.281\,s

e) The velocity of the projectile when it hits the ground is:

v(2.602\,s) = 25.5-9.8\cdot (5.281\,s)

v(2.602\,s) = -26.254\,\frac{m}{s}

4 0
3 years ago
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